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Molodets [167]
3 years ago
12

A 1.89 kg object on a frictionless horizontal track is attached to the end of a horizontal spring whose force constant is 4.89 N

/m. The object is displaced 4.73 m to the right from its equilibrium position and then released, which initiates simple harmonic motion. What is the magnitude of the force acting on the object 3.8 s after it is released? Answer in units of N.
Physics
1 answer:
mixas84 [53]3 years ago
4 0

To solve this problem, apply the concepts related to the simple harmonic movement. We will start by finding the angular velocity, essential to find the position of displacement of the spring with the data provided. With displacement we will apply Hooke's law.

A ) Position of the object is

x = Acos(\omega t)

The angular frequency of the object is

\omega = \sqrt{\frac{k}{m}}

\omega = \sqrt{\frac{4.89}{1.89}}

\omega =1.60851 rad/s

Replacing at the first equation we have that

x = (4.89)cos((1.60851)(3.8))

x = 4.8188m

Now the force is

F = -kx

F = - (4.89)(4.8188)

F = -23.5639N

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A skier leaves the horizontal end of a ramp with a velocity of 31.0 m/s and lands 156.3 m from the base of a ramp how high is th
BartSMP [9]

<u>Answer:</u>

The height of ramp = 124.694 m

<u>Explanation:</u>

Using second equation of motion,

s = ut + \frac{1}{2}at^2

From the question,

u = 31 m/s; s = 156.3 m, a=0

substituting values

156.3 = 31\times t + 0

t = \frac{156.3}{31 }

= 5.042 s

Similary, for the case of landing

t = 5.042 s; initial velocity, u =0

acceleration = acceleration due to gravity, g = 9.81 m/s^2

Substituting in h = ut + \frac{1}{2}gt^2

h = 0 + \frac{1}{2} \times 9.81 \times (5.042)^2

h = 124.694 m

So height of ramp = 124.694 m

3 0
3 years ago
1. The planet Jupiter completes a revolution of the sun in 11.5 years. Express it in seconds. Given that one year= 3.154 × 10^7
xenn [34]

Answer:

The planet Jupiter completes one revolution of the sun in 362710000 seconds. Long time, right?

Explanation:

3.154x10^7=3.154x10000000=31540000

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kirill115 [55]

Answer:

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Answer:

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