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Anika [276]
3 years ago
6

How does Bohr’s model of the atom compare with Thomson’s model? They both describe atoms as small, indivisible spheres. They bot

h describe electrons as moving around the nucleus. They both describe electrons as being surrounded by the positive matter. They both describe atoms as being made up of positive and negative matter.
Physics
2 answers:
Vadim26 [7]3 years ago
8 0
<span>They both describe atoms as being made up of positive and negative matter.</span>
Snowcat [4.5K]3 years ago
7 0

Answer:

They both describe atoms as being made up of positive and negative matter.

Explanation:

In both Bohr's model and Thomson model, the atom consists of positively-charged matter and negatively-charged matter. However, the structure of the atom in the two models is totally different:

- in Thomson's model, the atom consists of a large sphere of uniform positive charge, and electrons (which are negatively charged) are scattered all around inside this sphere

- In Bohr's model, the atom consists of a small, positively charged nucleus, while the electrons (negatively charged) orbit around the nucleus in precise orbits.

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A reconnaissance plane flies 404 km awayfrom its base at 730 m/s, then flies back to its base at 1095 m/s.What is it’s average s
elena-14-01-66 [18.8K]

The average speed of the plane is 875.999 m/s.

Average speed can be defined as the ratio of total distanced travelled by the object to that of total time taken to cover the distance.

Mathematically, Average speed = Av = \frac{Total Distance}{Total Time}

According to the question,

Speed of the plane away from its base V₁ = 730 m/s

Speed of the plane when it flies back V₂ = 1095 m/s

Plane flies the distance D = 404 km

Total Distance covered by the plane S = 404 * 2 km

(because the distance travelled by the plane when going away from the base and then flying back to the base is same)

Therefore S = 808 km = 808 ˣ 10³ m

Time taken by the plane while flying away from the base T₁ = \frac{D}{V1}

T₁ =  \frac{404000}{730} = 553.425 s

Time taken by the plane while flying back to the base T₂ = \frac{D}{V2}

T₂ =  \frac{404000}{1095} = 368.949s

Total Time T = T₁ + T₂ = 922.375 s

Therefore  Av = \frac{Total Distance}{Total Time}

= \frac{D}{T} m/s

=  \frac{808000}{922.375}  m/s

= 875.999 m/s

The average speed of the plane will be 875.999 m/s.

To know more about Average speed,

brainly.com/question/28641761

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1 year ago
a baseball is pitched with a speed of 35.0m/s. how long does it take the ball to travel 18.4 m from the pitchers mound to home p
Vlad [161]
Given the speed and the distance, to find time you can use the formula speed is equal to distance over time. From there you can manipulate the equation for time to equal the distance divided by speed. Time is equal to 18.4 meters divided by 35m/s which equals 0.526 seconds.

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A vector is a quantity or phenomenon that has two independent properties: magnitude and direction.
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Answer:

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Explanation:

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Answer:

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