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Anika [276]
2 years ago
6

How does Bohr’s model of the atom compare with Thomson’s model? They both describe atoms as small, indivisible spheres. They bot

h describe electrons as moving around the nucleus. They both describe electrons as being surrounded by the positive matter. They both describe atoms as being made up of positive and negative matter.
Physics
2 answers:
Vadim26 [7]2 years ago
8 0
<span>They both describe atoms as being made up of positive and negative matter.</span>
Snowcat [4.5K]2 years ago
7 0

Answer:

They both describe atoms as being made up of positive and negative matter.

Explanation:

In both Bohr's model and Thomson model, the atom consists of positively-charged matter and negatively-charged matter. However, the structure of the atom in the two models is totally different:

- in Thomson's model, the atom consists of a large sphere of uniform positive charge, and electrons (which are negatively charged) are scattered all around inside this sphere

- In Bohr's model, the atom consists of a small, positively charged nucleus, while the electrons (negatively charged) orbit around the nucleus in precise orbits.

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Hatshy [7]
The answer is 833.3 kg
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A 2000 kg truck traveling north at 34 km/h turns east and accelerates to 58 km/h. (a) What is the change in the truck's kinetic
barxatty [35]

Explanation:

It is given that,

Mass of the truck, m = 2000 kg

Initial velocity of the truck, u = 34 km/h = 9.44 m/s

Final velocity of the truck, v = 58 km/h = 16.11 m/s

(a) Change in truck's kinetic energy, \Delta E=\dfrac{1}{2}m(v^2-u^2)

\Delta E=\dfrac{1}{2}\times 2000\ kg\times (16.11^2-9.44^2)

\Delta E=170418.5\ J

\Delta E=1.7\times 10^5\ J

(b) Change in momentum of the truck, \Delta p=m(v-u)

\Delta p=2000\ kg\times (16.11-9.44)

\Delta p=13340\ kg-m/s

Hence, this is the required solution.

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3 years ago
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mixas84 [53]
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1 year ago
A speeder passes a parked police car at a constant speed of 23.3 m/s. At that instant, the police car starts from rest with a un
kotegsom [21]

Answer:

t = 16.94 s

Explanation:

t is the time passes before police catch the speeder

speed of speeder Vo = V = 23.3 m/s

T = t

Police Info

Vo = 0 m/s

a = 2.75 m/s^2

t = t

Now,

displacement of the police car = displacement of the speeder.

x_{police} = Vo *t + 1/2 at^2

since Vo = 0

x police = 1/2 at^2

x police = 1/2 (2.75)(t)^2

Now the displacement of speeder is

x_{speeder} = Vt

x_{speeder} = 23.3 t

x_{speeder} = x_{police}

23.3 t = 1/2 * 2.75 t^2

23.3 t = 1.375 t^2

t = 23.3\1.375

t = 16.94

t = 16.94 s

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2 years ago
What type of country is described by low birth rates, lower infant mortality rates, and longer life expectancy?
Gala2k [10]
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