Answer:
v = 54.2 m / s
Explanation:
Let's use energy conservation for this problem.
Starting point Higher
Em₀ = U = m g h
Final point. Lower
= K = ½ m v²
Em₀ = Em_{f}
m g h = ½ m v²
v² = 2gh
v = √ 2gh
Let's calculate
v = √ (2 9.8 150)
v = 54.2 m / s
Explanation:
<em>a)Which of the two has uniform acceleration?</em>
Acceleration is the second derivative of position. The acceleration of the first particle is:
x = 4t² − 2t
v = 8t − 2
a = 8
The acceleration of the second particle is:
x = 6t³ + 8t
v = 18t² + 8
a = 36t
The first particle has uniform acceleration.
<em>b)Which one is likely to come to rest at some time during its motion?</em>
The particles come to rest when v = 0. The first particle's velocity has a real zero at t = 4. The second particle's velocity has only imaginary zeros, meaning v is never 0.
This is called the perihelion.
Acceleration will always be samei.e.
Acceleration=g= 9.81 m/s^2
