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Ray Of Light [21]
3 years ago
5

An object has a kinetic energy of 14 J and a mass of 17 kg , how fast is the object moving?

Physics
2 answers:
lisabon 2012 [21]3 years ago
6 0
v ^{2} = Joules ÷ (0.5×Kilograms)

14J ÷ 8.5 = 1.64705882

Remember, 1.64705882 = v², so we need to find the square root.

The square root of 1.64705882 is 1.283377894464448

Hope this helps! 
valkas [14]3 years ago
4 0

Answer:

1.283377894464448

Explanation:

Big brain

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3. A model rocket is launched straight upward at 58.8 m/s.
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a). 6 seconds

b). 12 seconds

c). 176.4 meters

Explanation:

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   v = u - gt

where v = final velocity

u = initial velocity = 58.8 m per sec

g = gravitational pull = 9.8 m per sec²

t = duration of the flight

At the peak height,

v = 0

Therefore, 0 = 58.8 - (9.8)(t)

t =  \frac{58.8}{9.8}

 = 6 seconds

b). Total time of flight = 2(Time taken to go up)

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c). Formula to get the peak height is,

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8 0
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