<span>To calculate the number of moles of aluminum, sulfur, and oxygen atoms in 4.00 moles of aluminum sulfate, al2(so4)3. We will simply inspect the "number" of aluminum, sulfur, and oxygen atoms available per one mole of the compound. Here we have Al2(SO4)3, which means that for every mole of aluminum sulfate, there are 2 moles of aluminum, 3 (1 times 3) moles of sulfur, and 12 (4x3) moles of oxygen. Since we have four moles of Al2(SO4)3 given, we simply multiply 4 times the moles present per 1 mole of the compound. So we have 4x2 = 8 moles of Al, 4x3 = 12 moles of sulfur, and 4x12 = 48 moles of oxygen.
So the answer is:
8,12,48
</span>
Answer:
"The sun warms up parts of the oceans. Warm waters rise just like warm air rises. So, as the warmer ocean waters begin to rise in a particular area, the cooler ocean waters from a different area will move in to replace the warmer ocean waters, and this creates our ocean currents."
Explanation:
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Answer:
LOL YOUR PFP OMG SO FUNNY
<h3>
Answer:</h3>
81.9 grams
<h3>
Explanation:</h3>
From the question we are given;
- Half-life of C-14 is 5730 years
- Original mass of C-14 (N₀) = 150 grams
- Time taken, t = 5000 years
We are required to determine the mass left after 5000 years
- N = No(1/2)^t/T, where N is the remaining mass, N₀ is the original mass, t is the time taken and T is the half-life.
t/T = 5000 yrs ÷ 5730 yrs
= 0.873
N = 150 g ÷ 0.5^0.873
= 150 g × 0.546
= 81.9 g
Therefore, the mass of C-14 left after 5000 yrs is 81.9 g
Answer:be careful and relax
Explanation: