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160 g of SO3 are needed to make 400 g of 49% H2SO4.
<h3>How many grams of SO3 are required to prepare 400 g of 49% H2SO4?</h3>
The equation of the reaction for the formation of H2SO4 from SO3 is given below as follows:

1 mole of SO3 produces 1 mole of H2SO4
Molar mass of SO3 = 80 g/mol
Molar mass of H2SO4 = 98 g/mol
80 g of SO3 are required to produce 98 og 100%H2SO4
mass of SO3 required to produce 400 g of 100 %H2SO4 = 80/98 × 400 = 326.5 g of SO3
Mass of SO3 required to produce 49% of 400 g H2SO4 = 326.5 × 49% = 160 g
Therefore, 160 g of SO3 are needed to make 400 g of 49% H2SO4.
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Answer:
The molar mass of the compound given is 182.182 g/mol.
Explanation:
To calculate the molar mass of the compound, we must multiply the number of moles of each element by the the individual molar mass of each element and add them together.
Let's start with Calcium. The molar mass of Calcium is 40.078. In this compound, we have three moles of Calcium, so we should multiply this number by 3.
40.078 g/mol * 3 mol = 120.234 g
Now, let's do the same for Phosphorus.
30.974 g/mol * 2 g/mol = 61.948 g
To find the molar mass of the entire compound, we should add these two values together.
120.234 g + 61.948 g = 182.182 g
Therefore, the correct answer is 182.182 g/mol.
Hope this helps!
The answer is covalent bond