<h2>
</h2><h3>kinetic energy is given as</h3>
KE = (0.5) m v²
given that : v = speed of the bottle in each case = 4 m/s when m = 0.125 kg
KE = (0.5) m v² = (0.5) (0.125) (4)² = 1 J
when m = 0.250 kg KE = (0.5) m v² = (0.5) (0.250) (4)² = 2 J
when m = 0.375 kg KE = (0.5) m v² = (0.5) (0.375) (4)² = 3 J
when m = 0.0.500 kg KE = (0.5) m v² = (0.5) (0.500) (4)² = 4 J
Answer:
Work done = 0.3142 Nm
Explanation:
Mass of Object is 50 g
Circular path of radius is 10 cm ⇒ 0.1 m
Work done = Force × Distance = ?
*Distance moved (circular path) ⇒ Circumference of the circular path
2πr = 2 × 3.142 × 0.1 ⇒ 0.6284 m
*Force that is enough to move a 50 g must be equal or more than its weight.
therefore convert 50 grams to newton = 0.5 N
Recall that; work done is force times distance
∴ 0.5 N × 0.6284 m
Work done = 0.3142 Nm
A transform fault boundary is the correct answer.
The problem is asking the maximum separation between the telescope in the moon and mars. To tell you frankly, I have no idea how to calculate this by I research the answer which I will give to you and the clue that I just know is that the distance should be in kilometers and the telescopes diameter could affect the minimum separation between the two object. With that the answer would be 422,700 km
Answer:350.92 KJ/kg
Explanation:
Given the process is reversible adiabatic i.e it is isentropic
From steam table
For isentropic process
at
Therefore Work output of the turbine per unit mass of steam is =
=3317.03-2966.11
=350.92 KJ/kg