The graph represents the displacement of an object from its starting point as a function of time t. The object is traveling alon
1 answer:
Based on the given displacement vs time graph, the object is at rest at a time interval of: B. 2 to 3 seconds
<h3>What is a displacement vs time graph?</h3>A displacement vs time graph can be defined as a type of graph that is used to graphically represent the distance traveled (covered) or displacement experienced by an object from its starting position with respect to the time when it has started moving.
In Science, a physical object being at rest simply means that the position of the object is not changing with respect to time. Thus, both the slope and velocity of the physical object would be equal to zero when it is at rest.
Between 0 to 2 seconds on the given displacement vs time graph (see attachment), this object is traveling at a constant, positive velocity. However, at a time interval of 2 to 3 seconds the object is at rest.
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Answer:
The centripetal acceleration changed by a factor of 0.5
Explanation:
Given;
first radius of the horizontal circle, r₁ = 500 m
speed of the airplane, v = 150 m/s
second radius of the airplane, r₂ = 1000 m
Centripetal acceleration is given as;
At constant speed, we will have;
a₂ = 0.5a₁
Therefore, the centripetal acceleration changed by a factor of 0.5
Answer:
Answer
Time period T = 1.50 s
time t = 40 s
r = 6.2 m
a)
Angular speed ω = 2π/T
=
= 4.189 rad/s
Angular acceleration α =
=
= 0.105 rad/s²
Tangential acceleration a = r α = 6.2 x 0.105 = 0.651 m/s²
b)The maximum speed.
v = 2πr/T
=
= 25.97 m/s
So centripetal acceleration.
a =
=
= 108.781 m/s^2
= 11.1 g
in combination with the gravitation acceleration.