A small ball of mass m is
1 answer:
Answer:
E) V=(m/M)v
Explanation:
Given that
Mass of the small ball = m
Initial velocity of the small ball = v
Mass of the larger ball = m
Initial velocity of the larger ball = 0
After the collision
The velocity of the small ball = 0
The velocity of the larger ball = V
There is no any external force that is why linear momentum will be conserve.
From linear momentum conservation
Pi=Pf
m v + M x 0 = m x 0 + M V
m v +0 = 0 + M V
Therefore the answer will be E.
E) V=(m/M)v
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Answer:
The spring constant of the spring is 47.62 N/m
Explanation:
Given that,
Mass that is attached with the spring, m = 29 g = 0.029 kg
The spring makes 20 complete vibrations in 3.1 s. We need to find the spring constant of the spring. We know that the number of oscillations per unit time is called frequency of an object. So,
f = 6.45 Hz
The frequency of oscillator is given by :
k is the spring constant
k = 47.62 N/m
So, the spring constant of the spring is 47.62 N/m. Hence, this is the required solution.