All categories

4 years ago

What is pressure? A)Shown in picture B)Shown in picture C)Shown in picture D)Shown in picture

Physics

1 answer:

mr Goodwill [35]4 years ago

6 0

Answer:

The force exerted on a given area.

Option B is the right option.

Explanation:

<h2>About pressure</h2>

Pressure is defined as force acting per unit area. It's SI unit is Pascal or N/m^2.

Formula to find pressure is:

$\frac{thrust(f)}{area(a)}$

The force acting perpendicular on a surface is called the thrust. It is a vector quantity.

One Pascal pressure

One Pascal pressure is defined as the pressure exerted in a surface of area m^2 by the thrust of 1 N

Hope this helps ..

Good luck on your assignment.....

You might be interested in

Write a letter to ur mother living in

Westkost [7]

Answer:

no....

Explanation:

5 0

3 years ago

The current world-record motorcycle jump is 77.0 m, set by Jason Renie. Assume that he left the take-off ramp at 13.0° to the ho

kotegsom [21]

Answer:

The take-off speed is 41.48 $\frac{m}{s}$

Explanation:

Given :

Range $R = 77$ m

Projectile angle $\alpha =$ 13°

From the formula of range,

$R = \frac{v_{o} ^{2} }{g} \sin 2\alpha$

Find the velocity from above equation,

$v_{o} = \sqrt{\frac{gR}{\sin 2 \alpha } }$

$v_{o} = \sqrt{\frac{9.8 \times 77}{\sin 26} }$ ( ∵ $g = 9.8$ $\frac{m}{s^{2} }$ )

$v_{o} = 41.48$ $\frac{m}{s}$

Therefore, the take-off speed is 41.48 $\frac{m}{s}$

7 0

4 years ago

A ball is thrown straight up from the ground with speed v0. At the same instant, a second ball is dropped from rest from a heigh

dlinn [17]

Answer:

a) t = H/v0

b) H = -(v0)²/g

Explanation:

Hi there!

a)The position of the balls can be calculated using the following equation:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the ball at time t.

y0 = initial height.

v0 = initial velocity.

g = acceleration due to gravity.

t = time.

For the ball that is thrown upwards, the initial height is zero, then, the equation can be written as follows:

y = v0 · t + 1/2 · g · t²

The second ball is initially at a height H and the initial velocity is zero. The equation of height for the second ball will be:

y = H + 1/2 · g · t²

When the two balls collide, their height is the same. Then, equalizing both equations we can obtain the time at which they collide:

v0 · t + 1/2 · g · t² = H + 1/2 · g · t²

v0 · t = H

t = H/v0

b) When the first ball is at the highest point its velocity is zero. Using the equation of velocity we can find the time at which the ball is at that point. The equation of velocity is the following:

v = v0 + g · t

At the highest point v = 0.

0 = v0 + g · t

Solving for t:

-v0/g = t

The time at which the first ball is at the highest point is t = -v0/g

The time at which both balls collide was calculated above:

t = H/v0

Then, equalizing both times and solving for H:

H/v0 = -v0/g

H = -v0/g · v0

H = -(v0)²/g

3 0

4 years ago

Bolt starts the race not moving, but then increased his speed until he reaches a top speed. Once Bolt reaches his top speed he m

LekaFEV [45]

Answer:

Explanation:

In order to maintain speed, a moving object or person must move at a constant velocity. Accelerating will increase the speed while decelerating will reduce the speed.

Hence, for Bolt to be able to maintain the top speed for a few seconds, he needs to move at a constant velocity.

The correct option is a.

7 0

3 years ago

Can some one help me ;-;

enyata [817]

Answer: The first answer for the first problem, and the 2nd answer for the second problem

Explanation: For the first one, if it is absolute zero, the molecules would not move at all.

For the second one, the temperature of the sample will increase due to the movement.

6 0

3 years ago