To solve this problem we must rely on the equations of the simple harmonic movement that define the period as a function of length and gravity as
Where
l = Length
g = Gravity
Re-arrange to find L,
Our values are given as
Replacing,
Therefore the height would be 25.348m
Answer:
A. The pressure denoted as Pa and Pb at the surfaces of A and B in the tube is
PA= Pgas
PB= Patmos
B. The second sketch
C. The gas pressure is
Pgas= Patmos+ rho.g(h2-h1)
= 1atm + rho.g (h2-h1)
Explanation:
The ratio of the intensity between light intensity that emerges from the last filter and unpolarized light of intensity, I₀ is It/I₀ = 0.2925
To answer the question, we need to know what polarization of light is.
<h3>What is polarization of light?</h3>
This is when the electric field vector of light is oscillating in one plane.
- Now for light of intensity I' which is initially unpolarized, its intensity after polarization is I = 1/2I'.
- Also, for light initially polarized, its intensity after polarization is I"' = I"cos²Ф where Ф is the angle between the initial direction and the direction of polarization.
<h3>Intensity of light through each polarized filter</h3>
Given that we have 7 polarizing filters, each rotated 17° cw with respect to the previous filter.
So, since the light is initially unpolarized,
- The intensity through the first polarizing filter is I₁ = 1/2I₀ where I₀ is the initial intensity.
- The intensity through the second polarizing filter is I₂ = I₁cos²17°= 1/2I₀cos²17°
- The intensity through the third polarizing filter is I₃ = I₂cos²17° = 1/2I₀cos⁴17°
- The intensity through the fourth polarizing filter is I₄ = I₃cos²17° = 1/2I₀cos⁶17°
- The intensity through the fifth polarizing filter is I₅ = I₄cos²17° = 1/2I₀cos⁸17°
- The intensity through the sixth polarizing filter is I₆ = I₅cos²17° = 1/2I₀cos¹⁰17°
- The intensity through the seventh polarizing filter is I₇ = I₆cos²17° = 1/2I₀cos¹²17°.
<h3>The ratio of the intensity between light intensity that emerges from the last filter and unpolarized light of intensity</h3>
Since I₇ is the last intensity I₇ = It = 1/2I₀cos¹²17°.
So, It/I₀ = 1/2cos¹²17°
= 1/2(0.9563)¹²
= 1/2 × 0.5850
= 0.2925
So, the ratio of the intensity between light intensity that emerges from the last filter and unpolarized light of intensity, I₀ is It/I₀ = 0.2925
Learn more about intensity of polarized light here:
brainly.com/question/25402491
Answer:
Part a)
Part b)
Part c)
Explanation:
As we know that acceleration is rate of change in velocity of the object
So here we know that
Part a)
differentiate x and y two times with respect to time to find the acceleration
Now the acceleration of the object is given as
at t= 1.1 s we have
now the net force of the object is given as
now magnitude of the force will be
Part b)
Direction of the force is given as
Part c)
For velocity of the particle we have
now at t = 1.1 s
now the direction of the velocity is given as
