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3241004551 [841]
3 years ago
8

Jill is pushing a box across the floor. Which represents the upward force perpendicular to the floor?

Physics
2 answers:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

c fn

Explanation:

the answer is c.....

iragen [17]3 years ago
5 0

Answer: C: Fn

Explanation:

I got it right on the edgenuity quiz

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A solid conducting sphere with radius R that carries positive charge Q is concentric with a very thin insulating shell of radius
Nostrana [21]

Explanation:

Gauss Law relates the distribution of electric charge to the resulting electric field.

Applying Gauss's Law,

                              EA = Q / ε₀

Where:

E is the magnitude of the electric field,

A is the cross-sectional area of the conducting sphere,

Q is the positive charge

ε₀ is the permittivity

We be considering cases for the specified regions.

<u>Case 1</u>: When r < R

The electric field is zero, since the enclosed charge is equal to zero

                                            E(r) = 0

<u>Case 2</u>: When R < r < 2R

The enclosed charge equals to Q, then the electric field equals;

                              E(4πr²) = Q / ε₀

                              E = Q / 4πε₀r²

                              E = KQ /r²

Constant K = 1 / 4πε₀ = 9.0 × 10⁹ Nm²/C²

<u>Case 3</u>: When r > 2R    

The enclosed charge equals to Q, then the electric field equals;

                               E(4πr²) = 2Q / ε₀

                               E = 2Q / 4πε₀r²

                               E = 2KQ /r²        

4 0
3 years ago
In the Bohr model of the hydrogen atom, an electron({rm mass};m=9.1; times 10^{ - 31;}{rm kg}) orbits a proton at a distance of
max2010maxim [7]

Answer:

n=6.56×10¹⁵Hz

Explanation:

Given Data

Mass=9.1×10⁻³¹ kg

Radius distance=5.3×10⁻¹¹m

Electric Force=8.2×10⁻⁸N

To find

Revolutions per second

Solution

Let F be the force of attraction

let n  be the number of revolutions per sec made by the electron around the nucleus then the centripetal force is given by

F=mω²r......................where ω=2π  n

F=m4π²n²r...............eq(i)

as the values given where

Mass=9.1×10⁻³¹ kg

Radius distance=5.3×10⁻¹¹m

Electric Force=8.2×10⁻⁸N

we have to find n from eq(i)

n²=F/(m4π²r)

n^{2} =\frac{8.2*10^{-8} }{9.11*10^{-31}* 4\pi^{2} *5.3*10^{-11}  }\\ n^{2}=4.31*10^{31}\\ n=\sqrt{4.31*10^{31}}\\ n=6.56*10^{15}Hz

8 0
3 years ago
A) Millions of years of rain and wind
barxatty [35]

Answer:

B. Millions of years of high pressure and temperature.

  • Millions of years of high pressure and temperature the ancient forests turn into fossil fuels.

Explanation:

Fossil fuels were formed from the dead remains of living organisms millions of years ago. They were formed under high pressure and high temperature.

  • Coal : about 300 million years ago the earth had this forest in low lying wetland areas. Due to natural processes like flooding, these forest god buried under the soil. As more soil deposited over them, they were compressed. Under high pressure and high temperature, dead plants got slowly converted into coal.
  • Petroleum : Petroleum was formed from organisms living in the sea. As these organisms died, their bodies settled at the bottom of the sea and got covered with layers of soil and clay. Over millions of years, absence of air, high pressure and high temperature transformed the dead organisms into Petroleum.

Coal, Petroleum and natural gas are fossil fuels.

6 0
2 years ago
A soccer goal is 2.44 m high. A player kicks the ball at a distance 13 m from the goal at an angle of 40°, and the ball just hit
Vera_Pavlovna [14]

Let <em>v</em> denote the initial speed of the ball. The ball's position at time <em>t</em> is given by the vector

\mathbf r(t)=v\cos40^\circ\,t\,\mathbf i+\left(v\sin40^\circ\,t-\dfrac g2t^2\right)\,\mathbf j

where <em>g</em> is the acceleration due to gravity with magnitude 9.80 m/s^2.

The ball reaches the goal 13 m away at time <em>t</em> such that

10\,\mathrm m=v\cos40^\circ t\implies t=\dfrac{10\,\mathrm m}{v\cos40^\circ}

at which point it attains a height of 2.44 m, so that

2.44\,\mathrm m=v\sin40^\circ\left(\dfrac{10\,\mathrm m}{v\cos40^\circ}\right)-\dfrac g2\left(\dfrac{10\,\mathrm m}{v\cos40^\circ}\right)^2

2.44\,\mathrm m=(10\,\mathrm m)\tan40^\circ-\dfrac12\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)\left(\dfrac{100\,\mathrm m^2}{v^2\cos^240^\circ}\right)

\implies\boxed{v\approx3.75\dfrac{\rm m}{\rm s}}

6 0
4 years ago
Which reverses the flow of current through<br> an electric motor?
Gennadij [26K]

Answer:

a commutator

Explanation:

6 0
3 years ago
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