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Keith_Richards [23]
3 years ago
12

Using the combined gas law, if the volume of a gas at 155kPa changes from 22L to 10L. What is the new pressure if the temperatur

e remains constant?
Chemistry
1 answer:
Deffense [45]3 years ago
5 0

Answer:

The answer to your question is  P2 = 342 kPa

Explanation:

Data

Pressure 1 = P1 = 155 kPa

Volume 1 = V1 = 22 l

Pressure 2 = P2 = ?

Volume 2 = V2 = 10 l

Temperature = constant

Process

1.- Write the equation of the combined gas law

                 P1V1/T1 = P2V2/ T2

Cancel T1 and T2 because they measure the same

                 P1V1 = P2V2

-Solve for P2

                 P2 = P1V1/V2

2.- Substitution

                 P2 = (155 x 22) / 10

3.- Simplification

                 P2 = 3410 / 10

4.- Result

                 P2 = 342 kPa

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The question is missing the data sets.

This is the complete question:

A single penny has a mass of 2.5 g. Abbie and James each measure the mass of a penny multiple times. Which statement about these data sets is true? 

O Abbie's measurements are both more accurate and more precise than James'.

O Abbie's measurements are more accurate, but less precise, than James'. 

O Abbie's measurements are more precise, but less accurate, than James'. 

O Abbie’s measurements are both less accurate and less precise than James'. 

Penny masses (g)

Abbie’s data                                        

2.5, 2.4, 2.3, 2.4, 2.5, 2.6, 2.6 

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2.4, 3.0, 3.3, 2.2, 2.9, 3.8, 2.9

Answer: first option, Abbie's measurements are both more accurate and more precise than James'.

Explanation:


1) To answer this question, you first must understand the difference between precision and accuracy.

<span>Accuracy is how close the data are to the true or accepted value.
</span>

<span>Precision is how close are the data among them, this is the reproducibility of the values.</span>

Then, you can measure the accuracy by comparing the means (averages) with the actual mass of a penny 2.5 g.

And you measure the precision by comparing a measure of spread, as it can be the standard deviation.

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Abbie’s data                      
                 
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Standard deviation: √  [ ∑ (x - mean)² / (n - 1) ] = 0.11


James’ data


Average = [2.4 + 3.0 + 3.3 + 2.2 + 2.9 + 3.8 + 2.9] / 7 = 2.56 ≈ 2.6


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2) The standard deviation of Abbie's data is smaller than that of Jame's data, so the Abbie's data are more precise.
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