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3 years ago

7

How much hereditary information is contain in a human sex cell

1 answer:

scoray [572]3 years ago

8 0

Answer:

one-half the amount

Explanation:

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While watching a small fireworks display from a building 204 feet tall, you observe a rocket that travels from ground to eye lev

faltersainse [42]

204 ft = 62.2 m
We know that the initial velocity of the rocket was 0, we can find its acceleration using:
s = ut + 1/2 at²
62.2 = 0.5a(6)²
a = 3.46 m/s²
Now, the final velocity of the rocket:
v = u + at
v = 3.46 x 6
v = 20.76 m/s = 68.1 ft/s

4 0

3 years ago

What is the current when a typical static charge of 0.234~\mu\text{c}0.234 μc moves from your finger to a metal doorknob in 0.59

Black_prince [1.1K]

The current is defined as the quantity of charge Q that passes through a certain location in a time $\Delta t$ :
$I= \frac{Q}{\Delta t}$
Using the data of the problem, we find:
$I= \frac{Q}{\Delta t} = \frac{0.234 \mu C}{0.595 \mu s}=\frac{0.234\cdot 10^{-6} C}{0.595 \cdot 10^{-6} s}=0.39 A$

4 0

3 years ago

This is a strong, short-lived magnet created by a looped electrical current.

Fed [463]

Answer:elctromagnetic :D

Explanation:

4 0

3 years ago

Show that the energy of a magnetic dipole m in a magnetic field B is U--m B

Juli2301 [7.4K]

Answer:

showm

Explanation:

Consider a dipole having magnetic moment 'm' is placed in magnetic field $\vec{B}$ then the torque exerted by the field on the dipole is

$\tau = m\times B$

$\tau=mBsin\alpha$

Now to rotate the dipole in the field to its final position the work required to be done is

$U=\int \tau d\alpha$

$U=\int mBsin\alpha d\alpha$

$U= -mBcos\alpha$

$U=-\vec{m\times \vec{B}}$

Minimum energy mB is for the case when m is anti parallel to B.

Minimum energy -mB is for the case when m is parallel to B.

5 0

3 years ago

How much energy is needed to heat and melt 3.0 kg of copper initially at 83°C?

Ne4ueva [31]

As we know that in order to melt the copper we need to take the temperature of copper to its melting point

So here heat required to raise the temperature of copper is given as

$Q = ms\Delta T$

We know that

melting temperature of copper = 1085 degree C

Specific heat capacity of copper = 385 J/kg C

now we have

$Q = 3(385)(1085 - 83)$

$Q = 1157310 J$

$Q = 1157.3 kJ$

now in order to melt the copper we know the heat required is

$Q = mL$

here we know that

L = 205 kJ/kg

now from above formula

$Q = 3(205) kJ$

$Q = 615 kJ$

now total heat required will be

$Q = 1157.3 kJ + 615 kJ$

$Q = 1772.3 kJ$

As we know that

$1 Cal = 4.18 kJ$

now we have

$Q = \frac{1772.3}{4.18} = 430 KCal$

6 0

2 years ago