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rodikova [14]
3 years ago
6

Select the correct answer. What is the enthalpy for the reaction represented in the following energy diagram? A. +200 kJ B. +350

kJ C. +150 kJ D. +250 kJ

Chemistry
1 answer:
Stella [2.4K]3 years ago
6 0

Answer:

Option C. +150KJ

Explanation:

Data obtained from the question include:

Heat of reactant (Hr) = 200KJ

Heat of product (Hp) = 350KJ

Change in enthalphy (ΔH) =..?

The enthalphy of the reaction can be obtained as follow:

Change in enthalphy (ΔH) = Heat of reactant (Hp) – Heat of reactant (Hr)

ΔH = Hp – Hr

ΔH = 350 – 200

ΔH = +150KJ

Therefore, the enthalphy for the reaction above is +150KJ

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If in the following diagram the substance is in the solid state during stage 1, what is happening during stage 2?
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3. Determine the pH of each of the following solutions. (Hint: See Sample Problem B.) a. 1.0 x 10-2 M HCI c. 1.0 x 10-MHI b. 1.0
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Answer:

a. pH = 2 b. pH = 3 c. pH = 1 d. Unanswerable

Explanation:

pH = -log[H+] OR pH = -log{H3O+]

                    and inversely

pOH = -log[OH-]

1. Determine what substance you are working with, (acid/base)

2. Determine whether or not that acid or base is strong or weak.

a. 1.0 x 10^-2M HCl

HCl is a strong acid, therefore it will dissociate completely into H+ and Cl- with all ions going to the H+, therefore, the concentration of HCl and concentration of H+ are going to be equal, meaning we simply take the negative logarithm of the concentration of HCl and that would equal pH

pH = -log[H+]

pH = -log(1.0x10^-2)

pH = 2

b. 1.0 x 10^-3M HNO3

HNO3 like part a, is a strong acid, therefore it would simply require you to take the negative logarithm of the concentration of the compound itself, to find its pH.

pH = -log[H+]

pH = -log(1.0 x 10^-3)

pH = 3

c. 1.0 x 10^-1M HI

Like the previous parts, HI is a strong acid

pH = -log[H+]

pH = -log(0.10)

pH = 1

d. HB isn't an element, nor is it a compound so that would be unanswerable.

3 0
3 years ago
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1 year =525600 mins

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The person lived for 80.66 years.

7 0
3 years ago
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Blababa [14]
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5 0
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