Question

LiNO3(aq) and Na2CO3(aq).If a solid forms when solutions containing these salts are mixed, write the ionic equation.

Answer 1

    The  ionic   equation  is as below

2Li + (aq)  +   CO₃²- →  Li₂CO₃ (s)

explanation

step 1:  write the   molecular  equation  

  2 LiNO₃ (aq)  + Na₂CO₃  (aq) →   Li₂CO₃ (s)   +2NaNO₃

Step 2 :  break  the soluble electrolyte  in ions

2 Li⁺ (aq)  +2NO₃⁻(aq) +  2Na⁺(aq)  + CO₃²⁻ (aq)  → Li₂CO₃  + 2Na⁺(aq)  +2NO₃⁻(aq)

cancel the   spectator  ion  (  2Na⁺ and 2No₃⁻)

The ionic  equation  is therefore

2Li⁺ (aq)  + CO₃²⁻(aq) →  Li₂CO₃ (s)

Answer 2

Answer:

The net ionic equation :

$2Li^+(aq)+CO_3^{2-}(aq)\rightarrow Li_2CO_3(s)$

Explanation:

When aqueous solution of lithium nitrate and sodium carbonate are a=mixed together they give solid precipitate of lithium carbonate and aqueous solution of sodium nitrate.

$2LiNO_3(aq) +Na_2CO_3(aq)\rightarrow Li_2CO_3(s)+2NaNO_3(aq)$

When lithium nitrate in its aqueous solution gives lithium ions and carbonate ions.

$2LiNO_3(aq)\rightarrow 2Li^+(aq)+2NO_3^{-}(aq)$

When sodium carbonate in its aqueous solution gives lithium ions and carbonate ions.

$Na_2CO_3(aq)\rightarrow 2Na^+(aq)+CO_3^{2-}(aq)$

When sodium nitrate in its aqueous solution gives lithium ions and carbonate ions.

$NaNO_3(aq)\rightarrow 2Na^+(aq)+NO_3^{-}(aq)$

$2Li^+(aq)+2NO_3^{-}(aq)+2Na^+(aq)+CO_3^{2-}(aq)\rightarrow Li_2CO_3(s)+2Na^+(aq)+2NO_3^{-}(aq)$

Cancelling out common ions i.e. spectators ions from both the sides, we get the net ionic equation :

$2Li^+(aq)+CO_3^{2-}(aq)\rightarrow Li_2CO_3(s)$