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mario62 [17]
3 years ago
14

Wood with a mass of 3.0 grams was burned in an open dish. The ashes weighed 1.2 grams.

Chemistry
1 answer:
mr_godi [17]3 years ago
7 0

The rest of the wood was burned into gases of equivalent weight.

<u>Explanation</u>:

The rest of the wood was burned into gases of equivalent weight.

  • When wood is burnt in the open air, with the help of oxygen and heat, it is transformed into carbon dioxide, water vapor, and ashes.
  • Ignition and combustion of wood mainly depend on pyrolysis which is also known as thermal combustion.
  • The loss in weight of the ashes is due to the fact that gases and water vapor are also formed due to the combustion of wood.

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Consider the reaction:
goldfiish [28.3K]

Answer:

K = Ka/Kb

Explanation:

P(s) + (3/2) Cl₂(g) <-------> PCl₃(g) K = ?

P(s) + (5/2) Cl₂(g) <--------> PCl₅(g) Ka

PCl₃(g) + Cl₂(g) <---------> PCl₅(g) Kb

K = [PCl₃]/ ([P] [Cl₂]⁽³'²⁾)

Ka = [PCl₅]/ ([P] [Cl₂]⁽⁵'²⁾)

Kb = [PCl₅]/ ([PCl₃] [Cl₂])

Since [PCl₅] = [PCl₅]

From the Ka equation,

[PCl₅] = Ka ([P] [Cl₂]⁽⁵'²⁾)

From the Kb equation

[PCl₅] = Kb ([PCl₃] [Cl₂])

Equating them

Ka ([P] [Cl₂]⁽⁵'²⁾) = Kb ([PCl₃] [Cl₂])

(Ka/Kb) = ([PCl₃] [Cl₂]) / ([P] [Cl₂]⁽⁵'²⁾)

(Ka/Kb) = [PCl₃] / ([P] [Cl₂]⁽³'²⁾)

Comparing this with the equation for the overall equilibrium constant

K = Ka/Kb

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