Answer:
92.49 %
Explanation:
We first calculate the number of moles n of AgBr in 0.7127 g
n = m/M where M = molar mass of AgBr = 187.77 g/mol and m = mass of AgBr formed = 0.7127 g
n = m/M = 0.7127g/187.77 g/mol = 0.0038 mol
Since 1 mol of Bromide ion Br⁻ forms 1 mol AgBr, number of moles of Br⁻ formed = 0.0038 mol and
From n = m/M
m = nM . Where m = mass of Bromide ion precipitate and M = Molar mass of Bromine = 79.904 g/mol
m = 0.0038 mol × 79.904 g/mol = 0.3036 g
% Br in compound = m₁/m₂ × 100%
m₁ = mass of Br in compound = m = 0.3036 g (Since the same amount of Br in the compound is the same amount in the precipitate.)
m₂ = mass of compound = 0.3283 g
% Br in compound = m₁/m₂ × 100% = 0.3036/0.3283 × 100% = 0.9249 × 100% = 92.49 %
Answer:
The correct term for the definition is Allele.
<span>Since the oil slick consists of a single layer, then the thickness of the oil slick is 0.488 nm. When we multiply the thickness of the oil slick by the area A, then we should get the volume of the oil slick 0.708 m^3.
We can set up an equation to find the area A.
(A)(0.488 nm) = 0.708 m^3
A = 0.708 m^3 / 0.488 nm
A = 0.708 m^3 / 0.488 X 10^{-9} m
A = (0.708 / 0.488) X 10^9 m^2
A = 1.45 X 10^9 m^2
The area of the oil slick is 1.45 X 10^9 m^2</span>
Hello!
When you're stretching a rubber band, you are giving the band potential energy, because when you stretch it out, you are getting energy ready for when you're going to release it, like energy waiting to be released.
Hope this helps! ☺♥
