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KiRa [710]
4 years ago
8

How is a warm-up different from a cooldown?

Physics
2 answers:
LekaFEV [45]4 years ago
5 0

Explanation:

A warm-up is to warm up your body and a cooldown is to cool down your body.

Hope this helps : )

grin007 [14]4 years ago
5 0
“Aerobic exercise: How to warm up and cool down
Done correctly, warming up and cooling down may offer help in reducing your risk of injury and improving your athletic performance.

By Mayo Clinic Staff
Before you jump on the elliptical machine or hit the running trails, consider doing a brief warmup first. And think about following your workout with a quick cool-down session. Sure, a warmup and cool-down may add a few minutes to your exercise routine, but they might also reduce stress on your heart and other muscles.

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Why warm up and cool down

Warmups and cool-downs generally involve doing your activity at a slower pace and reduced intensity.

Warming up helps prepare your body for aerobic activity. A warmup gradually revs up your cardiovascular system by raising your body temperature and increasing blood flow to your muscles. Warming up may also help reduce muscle soreness and lessen your risk of injury.

Cooling down after your workout allows for a gradual recovery of preexercise heart rate and blood pressure. Cooling down may be most important for competitive endurance athletes, such as marathoners, because it helps regulate blood flow. Cooling down doesn't appear to help reduce muscle stiffness and soreness after exercise, but more research is needed.

Although there's controversy about whether warming up and cooling down can prevent injuries, proper warmups and cool-downs pose little risk. Plus, they seem to give your heart and blood vessels a chance to ease into — and out of — an exercise session. So if you have the time, consider including a warmup and cool-down in your workout routine.

How to warm up

Warm up right before you plan to start your workout. In general, warm up by focusing first on large muscle groups, such as your hamstrings. Then you can do exercises more specific to your sport or activity, if necessary.

Begin by doing the activity and movement patterns of your chosen exercise, but at a low, slow pace that gradually increases in speed and intensity. This is called a dynamic warmup. A warmup may produce mild sweating, but generally won't leave you fatigued.

Here are some examples of warm-up activities:

To warm up for a brisk walk, walk slowly for five to 10 minutes.
To warm up for a run, walk briskly for five to 10 minutes.
To warm up for swimming, swim slowly at first and then pick up the tempo as you're able.
How to cool down

Cooling down is similar to warming up. You generally continue your workout session for five minutes or so, but at a slower pace and reduced intensity.

Here are some examples of cool-down activities:

To cool down after a brisk walk, walk slowly for five to 10 minutes.
To cool down after a run, walk briskly for five to 10 minutes.
To cool down after swimming, swim laps leisurely for five to 10 minutes.
A word about stretching

If stretching exercises are part of your workout routine, it's best to do them after the warm-up or cool-down phase, when your muscles are already warm.

Stretching can improve flexibility and range of motion about a joint. Stretching may also help improve your performance in some activities by allowing your joints to move through their full range of motion. However, studies haven't consistently shown that stretching helps prevent muscle soreness or injury.

Be kind to your body

Finding time for regular aerobic workouts — plus warming up and cooling down — can be challenging. But with a little creativity, you can probably fit it in. For example, walking to and from the gym can be your warmup and cool-down.

“
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A stuntman with a mass of 80.5 kg swings across a moat from a rope that is 11.5 m. At the bottom of the swing the stuntman's spe
goldenfox [79]

Answer:

  • No
  • 5.49 m/s

Explanation:

The net force required to accelerate the stuntman in a circular arc of radius 11.5 m will be ...

  F = mv²/r . . . . where this m is the mass being accelerated, v is the tangential velocity, and r is the radius.

Here, the net force needs to be ...

  F = (80.5 kg)(8.45 m/s)²/(11.5 m) . . . . . where this m is meters

  ≈ 499.8175 kg·m/s² = 499.8 N

Gravity exerts a force on the stuntman of ...

  F = mg = (80.5 kg)(9.8 m/s²) = 788.9 kg·m/s² = 788.9 N

Then the tension required in the rope/vine is ...

  499.8 N+788.9 N= 1288.7 N

This is more than the capacity of the rope, so we do not expect the stuntman to make it across the moat.

_____

The allowed net force for centripetal acceleration is ...

  1000 N -788.9 N = 211.1 N

Then the allowed velocity is ...

  211.1 = 80.5v²/11.5

  30.16 = v² . . . .  multiply by 11.5/80.5

  5.49 = v . . . . . . take the square root

The maximum speed the stuntman can have is 5.49 m/s.

_____

<em>Comment on crossing the moat</em>

The kinetic energy at the bottom of the swing translates to potential energy at the end of the swing. At the lower speed, the stuntman cannot rise as high, so will traverse a shorter arc. At 8.45 m/s, the moat could be about 16.8 m wide; at 5.49 m/s, it can only be about 11.5 m wide.

5 0
3 years ago
3. An astronaut on a space-walk swings a 0.5 kg metal tool in a circular path at the end of a cable 3.6 m long. The astronaut th
Semenov [28]

Answer:

Explanation:

2 km a hour

6 0
3 years ago
The spectra of most stars are dark-line spectra because ________.
pav-90 [236]
Because dark line spectra result from passing white light through ionized gasses and plasmas, which is what the atmosphere of stars are made of.  These frequencies are scattered by the star's atmosphere as it leaves the surface (photosphere) of the star, and don't make it to earth.
5 0
3 years ago
A proton moving at 8.00 106 m/s through a magnetic field of magnitude 1.72 T experiences a magnetic force of magnitude 7.20 10-1
gladu [14]

Answer:

19.1 deg

Explanation:

v = speed of the proton = 8 x 10⁶ m/s

B = magnitude of the magnetic field = 1.72 T

q = magnitude of charge on the proton = 1.6 x 10⁻¹⁹ C

F = magnitude of magnetic force on the proton = 7.20 x 10⁻¹³ N

θ = Angle between proton's velocity and magnetic field

magnitude of magnetic force on the proton is given as

F = q v B Sinθ

7.20 x 10⁻¹³ = (1.6 x 10⁻¹⁹) (8 x 10⁶) (1.72) Sinθ

Sinθ = 0.327

θ = 19.1 deg

4 0
4 years ago
How much voltage is in the primary coil if there are 3200 windings in the
Lesechka [4]

Answer:

Voltage in primary coil is 3.91 V

Explanation:

For transformer we know that the working principle is given as

\frac{V_1}{V_2} = \frac{N_1}{N_2}

here we know that

V_1 [tex] = voltage in primary coil[tex]V_2 = 25 V

N_1 = 500

N_2 = 3200

Now we have

\frac{V_1}{25} = \frac{500}{3200}

V_1 = 3.91 V

8 0
3 years ago
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