Exponent rules : (a^m)^n = a^(mn) and a^0 = 1
(4^9)^5 * 4^0 =
4^45 * 1 =
4^45 <==
This is rationalising the denominator of an imaginary fraction. We want to remove all i's from the denominator.
To do this, we multiply the fraction by 1. However 1 can be expressed in an infinite number of ways. For example, 1 = 2/2 = 3/3 = 4n^2 / 4n^2 (assuming n is not zero!). Let's express 1 as the complex conjugate of the denominator, divided by the complex conjugate of the denominator.
The complex conjugate of (3 - 2i) is (3 + 2i). Then do what I just said:
4/(3-2i) * (3+2i)/(3+2i) = 4(3+2i)/(3-2i)(3+2i) = (12+8i)/(9-4i^2) = (12+8i)/(9+4) = (12+8i)/13
This is the answer you are looking for. I hope this helps :)
Answer:
The fifth term is the middle term of nine, with coefficient given by all the ways of choosing 4 items out of 8
, namely the ways of choosing 4
a
's out of 8 binomial factors.
Step-by-step explanation:
1900 - 1300 = 6,000 more website hits on Tuesday.
When you rearrange the equation, you find that the solution is b)
