1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Degger [83]
3 years ago
12

Which of these processes helps extract energy from food?

Chemistry
1 answer:
Stels [109]3 years ago
7 0

Answer:  Proteins extract the energy from food via Enzymes.

You might be interested in
The combination of sucrose, sucrase, and water produces sucrase, glucose, and fructose. Which component of the reaction is the s
Pavlova-9 [17]

Answer:

Sucrose to is the substrate of the reaction because is a simple sugar( disaccharide) which produce glucose and fructose in the presence of sucrase or when it is hydrolysed.

6 0
2 years ago
A flask contains 0.83mol of neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is th
Angelina_Jolie [31]

Answer: 5.66 dm3

Explanation:

Given that:

Volume of neon gas = ?

Temperature T = 35°C

Convert Celsius to Kelvin

(35°C + 273 = 308K)

Pressure P = 0.37 atm

Number of moles N = 0.83 moles

Note that Molar gas constant R is a constant with a value of 0.0082 ATM dm3 K-1 mol-1

Then, apply ideal gas equation

pV = nRT

0.37atm x V = 0.83 moles x 0.0082 atm dm3 K-1 mol-1 x 308K

0.37 atm x V = 2.096 atm dm3

V = (2.096 atm dm3 / 0.37atm)

V = 5.66 dm3

Thus, the volume of the neon gas is 5.66 dm3

5 0
3 years ago
CO2 + H20. What is the total number of moles of Oz required to completely
maria [59]
I think the right answer is 2.5
7 0
3 years ago
The Same force is applied to a 300 kg go kart and 100 kg wagon at the beginning of the race. Which time is true about their acce
ELEN [110]
The wagon will accelerate at a faster pace. Since the wagon is lighter than the go kart, the same force will have a stronger effect
5 0
3 years ago
Find the percentage composition of a compound that contains 1.94 g of carbon, 0.48 g of hydrogen, and 2.58 g of sulfur.
Svetradugi [14.3K]

Answer : The percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

Explanation :

To calculate the percentage composition of element in sample, we use the equation:

\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100

Given:

Mass of carbon = 1.94 g

Mass of hydrogen = 0.48 g

Mass of sulfur = 2.58 g

First we have to calculate the mass of sample.

Mass of sample = Mass of carbon + Mass of hydrogen + Mass of sulfur

Mass of sample = 1.94 + 0.48 + 2.58 = 5.0 g

Now we have to calculate the percentage composition of a compound.

\%\text{ composition of carbon}=\frac{1.94g}{5.0g}\times 100=38.8\%

\%\text{ composition of hydrogen}=\frac{0.48g}{5.0g}\times 100=9.6\%

\%\text{ composition of sulfur}=\frac{2.58g}{5.0g}\times 100=51.6\%

Hence, the percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

3 0
3 years ago
Other questions:
  • What happens when light passes from air into water?
    12·1 answer
  • Which one of the following statements best describes the particles in a gas?
    12·1 answer
  • How can you determine the quantities of reactants and products in a chemical reaction
    15·1 answer
  • What is the significance of the symbol of an element?
    7·2 answers
  • Help me !!!!!!!!!!! Please
    6·1 answer
  • Which group has the highest ionization energies? Explain why.
    11·1 answer
  • Why is carbon-12 the only isotope with an atomic mass that is a whole number?
    15·1 answer
  • Use the reactions below and their equilibrium constants to predict the equilibrium constant for the reaction 2A(s)⇌3D(g). A(s) ⇌
    11·1 answer
  • 36) What is the mass of a 4.259 g/cm substance which takes up 250.00 cm of space?
    10·1 answer
  • A jar contains helium gas. what would happen if the lid of this Jar was removed
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!