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VladimirAG [237]
3 years ago
10

How to convert volts to electron volts?

Chemistry
1 answer:
SOVA2 [1]3 years ago
4 0

Answer:

How to convert volts to electron-volts

How to convert electrical voltage in volts (V) to energy in electron-volts (eV).

You can calculate electron-volts from volts and elementary charge or coulombs, but you can't convert volts to electron-volts since volt and electron-volt units represent different quantities.

Volts to eV calculation with elementary charge

The energy E in electron-volts (eV) is equal to the voltage V in volts (V), times the electric charge Q in elementary charge or proton/electron charge (e):

E(eV) = V(V) × Q(e)

The elementary charge is the electric charge of 1 electron with the e symbol.

So

electronvolt = volt × elementary charge

or

eV = V × e

Example

What is the energy in electron-volts that is consumed in an electrical circuit with voltage supply of 20 volts and charge flow of 40 electron charges?

E = 20V × 40e = 800eV

Volts to eV calculation with coulombs

The energy E in electron-volts (eV) is equal to the voltage V in volts (V), times the electrical charge Q in coulombs (C) divided by 1.602176565×10-19:

E(eV) = V(V) × Q(C) / 1.602176565×10-19

So

electronvolt = volt × coulomb / 1.602176565×10-19

or

eV = V × C / 1.602176565×10-19

Example

What is the energy in electron-volts that is consumed in an electrical circuit with voltage supply of 20 volts and charge flow of 2 coulombs?

E = 20V × 2C / 1.602176565×10-19 = 2.4966×1020eV

Explanation:

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Answer:

Cobalt and its derivatives act as a catalyst for some enzymatic functions, in this case, it acts as a cofactor.

Cobaloximes are effective electrocatalysts for the production of hydrogen and, therefore, functional models for hydrogenases.

Explanation:

Cobalt is a metal that participates directly in the synthesis of vitamin B12, necessary for the metabolism of various proteins, with megaloblastic anemia being one of the greatest evidences of a lack.

Its main function is that it integrates the vitamin B12 molecule, also called cyanocobalamin, so that lack of cobalt causes the same symptoms as vitamin B12 deficiency.

Vitamin B12 can only be synthesized by bacteria and for this a cobalt atom is required, in fact adult ruminants can synthesize enough vitamin B12 in the rumen provided they have an adequate supply of cobalt.

It acts as a catalyst for some enzymatic functions, in this case, it acts as a cofactor. Very important for example in the transfer of methyl groups, in this way cobalt, together with folic acid participate in the synthesis of methionine.

The dimethylglioxime (dmgH) complexes to the cobalt to give a series of complexes of Co (III), called cobaloxime, that having 4 positions coordinated to nitrogen in a coplanar way and forming a ring similar to the corrínico nucleus; If another substituent also has an N-heterocyclic nature, it can correctly simulate the B12 system.

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3 years ago
Which of the following is not produced in
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One way to ensure that scientific claims are valid is to analyze who is presenting the information: only trust information prese
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False

Explanation:

The best way to ensure scientific claims are valid is to subject them to various tests. Scientific claims has nothing to do with the body presenting them. Claims are authenticated following due scientific process.

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4 years ago
"What is the change of entropy for 3.0 kg of water when the 3.0 kg of water is changed to ice at 0"
Artyom0805 [142]

Q: What is the change of entropy for 3.0 kg of water when the 3.0 kg of water is changed to ice at 0 °C? (Lf = 3.34 x 105 J/kg)

Answer:

-3670.33 J/K

Explanation:

Entropy: This can be defined as the degree of randomness or disorderliness of a substance. The S.I unit of Entropy is J/K.

Mathematically,  change of Entropy can be expressed as,

ΔS = ΔH/T ....................................... Equation 1

Where ΔS = Change of entropy, ΔH = heat change, T = temperature.

ΔH = -(Lf×m).................................... Equation 2

Note: ΔH is negative because heat is lost.

Where Lf = latent heat of ice = 3.34×10⁵ J/kg, m = 3.0 kg, m = mass of water = 3.0 kg

Substitute into equation

ΔH = -(3.34×10⁵×3.0)

ΔH = - 1002000 J.

But T = 0 °C = (0+273) K = 273 K.

Substitute into equation 1

ΔS = -1002000/273

ΔS = -3670.33 J/K

Note: The negative value of ΔS shows that the entropy of water decreases when it is changed to ice at 0 °C

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