Stop and look to see if anything is coming
Answer:
Resistance will become 4 times the previous value
Explanation:
We have given current in the circuit i = 2.4 A
According to ohm's law current in the circuit is given by 
So
............eqn 1
Now voltage is increased to 4 times so new voltage = 4 V
And current in the circuit is same as 2.4 A
We have to fond the resistance so that after increasing voltage current will be same
So
..........eqn 2
Dividing eqn 1 and 2


So resistance will become 4 times the previous value
you would multiply 30 by 15. because its the weight times the distance.
Answer:
θ = 66.90°
Explanation:
we know that

I= intensity of polarized light =1
I_o= intensity of unpolarized light = 13
putting vales we get

⇒
therefore θ = 66.90°
To solve this problem we will apply the concept of centripetal acceleration. This type of acceleration is described as the product between the square of the angular velocity and the turning radius. Mathematically the expression can be expressed as

Here,
Angular velocity
r = Radius
Our values are given as,


Replacing,


Therefore the electron's centripetal acceleration is 