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3 years ago

A 2.0kg mass is attached to a horizontal spring having a spring constant of 0.05Nm.

Physics

1 answer:

Alex Ar [27]3 years ago

3 0

Good. You can do some very interesting experiments with that equipment.

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A crate is being lifted into a truck. If it is moved with a 2470 N force and 4850 J of work is done, then how far is the crate b

olchik [2.2K]

Answer:1.96m

Explanation:

Work=4850J

Force=2470N

Distance =work ➗ force

Distance =4850 ➗ 2470

Distance =1.96m

7 0

3 years ago

Describe how two isotopes of nitrogen differ from two nitrogen ions???PLEASE ANSWER 20 POINTS

Wewaii [24]

Nitrogen isotopes don't have a charge.

3 0

3 years ago

In a novel from 1866 the author describes a spaceship that is blasted out of a cannon with a speed of about 11.000 m/s. The spac

Elan Coil [88]

Answer:

$a=0.284\ m/s^2$

Explanation:

Given that,

Initially, the spaceship was at rest, u = 0

Final velocity of the spaceship, v = 11 m/s

Distance accelerated by the spaceship, d = 213 m

We need to find the acceleration experienced by the occupants of the spaceship during the launch. It is a concept based on the equation of kinematics. Using the third equation of motion to find acceleration.

$v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(11)^2-(0)^2}{2\times 213}\\\\a=0.284\ m/s^2$

So, the acceleration experienced by the occupants of the spaceship is $0.284\ m/s^2$ .

5 0

3 years ago

A circular grill of diameter 0.25 m has an emissivity of 0.8. If the surface temperature is maintained at 150°C, determine the r

Schach [20]

Answer:

the required electrical power when the room air and surroundings are at 30°C.= 52.51822 Watt

Explanation:

Power required to maintain the surface temperature at 150°C from 20°C

P= εσA(T^4-t^4)

P= power in watt

ε= emissivity

A= area of surface

T= 150°C= 423 K

t= 20°C= 303K

/sigma= 5.67×10^{-8} watt/m^2K^4

putting vales we get

$= 0.8\times5.67\times10^{-8} \pi\frac{0.25^4}{4}(423^4-303^4)$

P=52.51822 Watt

the required electrical power when the room air and surroundings are at 30°C.= 52.51822 Watt

4 0

3 years ago

A distance of 200 ft must be taped in a manner to ensure a standard deviation smaller than ± 0.04 ft. What must be the standard

Nutka1998 [239]

Answer:

The error in tapping is ±0.02828 ft.

Explanation:

Given that,

Distance = 200 ft

Standard deviation = ±0.04 ft

Length = 100 ft

We need to calculate the number of observation

Using formula of number of observation

$n=\dfrac{\text{total distance}}{\text{deviation per tape length}}$

Put the value into the formula

$n=\dfrac{200}{100}$

$n=2$

We need to calculate the error in tapping

Using formula of error

$E_{series}=\pm E\sqrt{n}$

$E=\dfrac{E_{series}}{\sqrt{n}}$

Put the value into the formula

$E=\dfrac{0.04}{\sqrt{2}}$

$E=\pm 0.02828\ ft$

Hence, The error in tapping is ±0.02828 ft.

3 0

4 years ago