In a free body diagram for an object projected upwards;
- the acceleration due to gravity on the object is always directed downwards.
- the velocity of the object is always in the direction of the object's motion.
An object projected upwards is subjected to influence of acceleration due to gravity.
As the object accelerates upwards, its velocity decreases until the object reaches maximum height where its velocity becomes zero and as the object descends its velocity increases, which eventually becomes maximum before the object hits the ground.
To construct a free body diagram for this motion, we consider the following;
- the acceleration due to gravity on the object is always directed downwards
- the velocity of the object is always in the direction of the object's motion.
<u>For instance:</u>
upward motion for velocity ↑ downward motion for velocity ↓
↑ ↓
↑ ↓
acceleration due to gravity ↓
↓
↓
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Answer:
Yes, there will be collision.
Explanation
Initial relative velocity u = 34-5.4 = 28.6 m/s
required final relative velocity v = 0
Acceleration , suppose be a .
Distance traveled =d = 160 m
Using the formula for relative motion,
v² - u² = 2as
0 - 28.6²=2as
a = - 2.55 m s⁻².
Since this required value is more than maximum braking deceleration so , there will be collision.
Answer
given,
t = 3 s
we know,
position of the particle
integrating both side
Position of the particle at t= 3 s
x = 182.98 ft
Distance traveled by the particle in 3 s is equal to 182.98 ft
now, particle’s acceleration
at t= 3 s
a = 2.98 ft/s²
acceleration of the particle is equal to 2.98 ft/s²
The correct answer to the question is : C)The problem is asking to solve for work; W = F × d
EXPLANATION:
As per the question, the distance covered by the object d = 29 m.
The force that acts on the object is F = 289 N.
We are asked to choose the correct equation for work done.
Work is said to be done on a body or by a body if the applied force has a component along the direction of displacement.
Mathematically work done W = force × displacement
= F × d
As per the question, we are given distance covered and applied force.
Hence, the correct equation for calculating work done by the object is equation C.
