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Sav [38]
3 years ago
8

!!!!!!!!!!!!!!!!!!! HELP !!!!!!!!!!!!!!!!!!!!!!!

Chemistry
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

B

Explanation:

Gain electrons

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A graduated cylinder is filled with 34.4 mL of water. A toy Car that weighs 43.672-g is Gently placed in the cylinder and the wa
Thepotemich [5.8K]

Answer:9.49g/mL

Explanation:

Mass of toy = 43.672g

Volume of water = 34.4mL

Volume of toy + volume of water = 39mL

Volume of toy = 39 — 34.4 = 4.6mL

Density = Mass /volume

Density = 43.672/4.6 = 9.49g/mL

8 0
3 years ago
Without consulting Appendix B, arrange each group in order of increasing standard molar entropy (S°). Explain.(c) SF₆(g), SF₄(g)
Andre45 [30]

The increasing order of standard molar entropy (S°) is as follow:

SF₄(g) < SF₆(g) < S₂F₁₀(g)

<h3>What is Entropy? </h3>

Entropy is defined as the randomness of the particle. It depends on temperature and pressure or number of particle per unit volume.

It is directly proportional to the temperature and pressure of the gas.

<h3>What is Standard Molar Entropy? </h3>

The standard molar entropy is defined as the entropy content of the one mole of pure substance at the standard state of temperature and pressure of interest.

The standard molar entropy is also defined as the total amount of entropy which 1 mole of the substance acquire, as it is brought from 0K to standard conditions of temperature and pressure.

The standard molar entropy depends on the molas mass of atom, molecules or compound.

SF₄(g) has lower standard molar entropy. Due to less complexity of this molecules.

While, complexity increases from SF₆(g) to S₂F₁₀(g). Therefore, the standard molar entropy of S₂F₁₀(g) is greater than SF₆(g).

Thus, we concluded that the increasing order of standard molar entropy (S°) is as follow:

SF₄(g) < SF₆(g) < S₂F₁₀(g)

learn more about standard molar entropy:

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7 0
2 years ago
The density of carbon in the form of diamond is 3.51 g/cm^3. if you have a small diamond with a volume of 0.0270 cm3 what is its
lora16 [44]
Hey there!:


density  = 3.51 g/cm³

Volume = 0.0270 cm³

Therefore:

D = m / V

3.51 = m / 0.0270

m = 3.51 * 0.0270

m = 0.09477 g 
3 0
3 years ago
Read 2 more answers
Part 1. Determine the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm. Show your work.
zaharov [31]

If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18 g/mol

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases.

An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given :

  • V = 2.4 L = 0.0024
  • P = 86126.25 Pa
  • T =  287 K
  • m = 0.622
  • R = 8.314

The ideal gas equation is given below.

n = PV/RT

n = 86126.25 x 0.0024 / 8.314 x 287

n = 0.622 / molar mass (n = Avogardos number)

Molar mass =  7.18 g

Hence, the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm is 7.18 g

More about the ideal gas equation link is given below.

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4 0
1 year ago
What is 140.2 in scientific notation
Akimi4 [234]

Answer:

1.402 * 10^2.

Explanation:

There are 3 digits before the decimal point so the exponent is 2.

4 0
3 years ago
Read 2 more answers
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