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Vitek1552 [10]
3 years ago
15

A beaker contains 2.06 mol of copper, and beaker b contains 222 grams of silver. which beaker contains the larger mass? which be

aker has the longer number of atoms?
Chemistry
1 answer:
svet-max [94.6K]3 years ago
6 0
Part (a): The masses
From the periodic table:
molar mass of copper = 63.5 grams
This means that:
mass of 2..06 moles = 2.06 * 63.5 = 130.81 grams
comparing this mass with the 222 grams of silver, we will find that the mass of silver is greater.

Part (b): The atoms:
number of moles = mass / molar mass
number of moles of silver = 222 / 107.8 = 2.059 moles
each mole contains Avogadro's number of atoms.
Since number of moles of copper is slightly larger than nuber of moles of silver, this means that the number of atoms in the copper sample would be more.
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The word root for a group of microorganisms living together is a. steriliz. b. prodrom. c. coloniza. d. nosocomi.
UkoKoshka [18]

The answer is C) Coloniza.

7 0
3 years ago
A 1.000 g sample of an unknown hydrate of cobalt chloride is gently dehydrated. The resulting mass is 0.546 g. The cobalt is iso
ira [324]

Answer:

Explanation:

From the 1 g sample you have:

0.546 grams of cobalt chloride

1-0.546=0.454 grams of water

Now:

1) The salt

Of the 0.546 g, 0.248 g are cobalt (Mr=58.9) and the rest id Cl (Mr=35.45):

n_{Co}=\frac{0.248 g}{58.9 g/mol}=4.21*10^{-3}mol

n_{Cl}=\frac{0.298 g}{35.45g/mol}=8.4*10^{-3}mol

Dividing:

\frac{n_{Cl}}{n_{Co}}=\frac{8.4*10^{-3}mol}{4.21*10^{-3}mol}=2

So the molecular formula will be:

CoCl_2

2) The water

The water's molecular weight is M=18 :

n_{w}=\frac{0.454g}{18g/mol}=0.025 mol

Bonding with the Co:

\frac{n_{w}}{n_{Co}}=\frac{0.025mol}{4.21*10^{-3}mol}=6

The complete formula of the hydrate:

CoCl_2*6 H_2O

8 0
4 years ago
To what volume (in mL) would you need to dilute 25.0mL of a 1.45 m solution of Kcl to make a 0.0245m solution of KCl
dezoksy [38]

Answer:

The answer is

<h2>1479.60 mL</h2>

Explanation:

In order to calculate the volume needed we use the formula

V_2 =  \frac{C_1V_1}{C_2}

where

C1 is the concentration of the stock solution

V1 is the volume of the stock solution

C2 is the concentration of the diluted solution

V2 is the volume of thevdiluted solution

From the question

C1 = 1.45 M

V1 = 25 mL

C2 = 0.0245 M

So we have

V_2 =  \frac{1.45 \times 25}{0.0245}   =  \frac{36.25}{0.0245}  \\  = 1479.59...

We have the final answer as

<h3>1479.60 mL</h3>

Hope this helps you

4 0
3 years ago
What is the purpose of molecular models?
dsp73

Answer: to see if the matter is a compound, mixture, or element.

Explanation:

can you please help with my most recent question :)

6 0
3 years ago
Elements riddle: Without my next door neighbor, I wouldn’t be worth 6 cents. Who am I?
zalisa [80]
If I understand this right, the two elements are Nickel and Copper, elements 28 and 28, respectively. A nickel is worth 5 cents, and a penny, originally comprised of copper, is worth one - the total being six cents.
7 0
3 years ago
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