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Vitek1552 [10]
3 years ago
15

A beaker contains 2.06 mol of copper, and beaker b contains 222 grams of silver. which beaker contains the larger mass? which be

aker has the longer number of atoms?
Chemistry
1 answer:
svet-max [94.6K]3 years ago
6 0
Part (a): The masses
From the periodic table:
molar mass of copper = 63.5 grams
This means that:
mass of 2..06 moles = 2.06 * 63.5 = 130.81 grams
comparing this mass with the 222 grams of silver, we will find that the mass of silver is greater.

Part (b): The atoms:
number of moles = mass / molar mass
number of moles of silver = 222 / 107.8 = 2.059 moles
each mole contains Avogadro's number of atoms.
Since number of moles of copper is slightly larger than nuber of moles of silver, this means that the number of atoms in the copper sample would be more.
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3 years ago
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Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) Kp=2.26×104 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under eac
valentinak56 [21]

Answer : The value of \Delta G_{rxn} is, 8.867kJ/mole

Explanation :

The formula used for \Delta G_{rxn} is:

\Delta G_{rxn}=\Delta G^o+RT\ln Q   ............(1)

where,

\Delta G_{rxn} = Gibbs free energy for the reaction

\Delta G_^o =  standard Gibbs free energy

R = gas constant = 8.314 J/mole.K

T = temperature = 25^oC=273+25=298K

Q = reaction quotient

First we have to calculate the \Delta G_^o.

Formula used :

\Delta G^o=-RT\times \ln K_p

Now put all the given values in this formula, we get:

\Delta G^o=-(8.314J/mole.K)\times (298K)\times \ln (2.26\times 10^{4})

\Delta G^o=-24839.406J/mole=-24.83\times 10^3J/mole=-24.83kJ/mole

Now we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

CO(g)+2H_2(g)\rightarrow CH_3OH(g)

The expression for reaction quotient will be :

Q=\frac{(p_{CH_3OH})}{(p_{CO})\times (p_{H_2})^2}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(1.4)}{(1.2\times 10^{-2})\times (1.2\times 10^{-2})^2}

Q=8.1\times 10^{5}

Now we have to calculate the value of \Delta G_{rxn} by using relation (1).

\Delta G_{rxn}=\Delta G^o+RT\ln Q

Now put all the given values in this formula, we get:

\Delta G_{rxn}=-24.83kJ/mole+(8.314\times 10^{-3}kJ/mole.K)\times (298K)\ln (8.1\times 10^{5})

\Delta G_{rxn}=8.867\times 10^3J/mole=8.867kJ/mole

Therefore, the value of \Delta G_{rxn} is, 8.867kJ/mole

3 0
2 years ago
2C₂H6 + 702 —>4C02 + 6H₂O
navik [9.2K]

Answer:

975.56×10²³ molecules

Explanation:

Given data:

Number of molecules of C₂H₆ = 4.88×10²⁵

Number of molecules of CO₂ produced  =  ?

Solution:

Chemical equation:

2C₂H₆  + 7O₂     →      4CO₂ + 6H₂O

Number of moles of C₂H₆:

1 mole = 6.022×10²³ molecules

4.88×10²⁵  molecules×1mol/6.022×10²³ molecules

0.81×10² mol

81 mol

Now we will compare the moles of C₂H₆ with CO₂.

                     C₂H₆          :             CO₂

                          2           :               4

                           81         :           4/2×81 = 162 mol

Number of molecules of CO₂:

1 mole = 6.022×10²³ molecules

162 mol ×6.022×10²³ molecules / 1 mol

975.56×10²³ molecules

8 0
2 years ago
Gas a (L^2. atm/mol^2) b(L/mol)
Amiraneli [1.4K]

Answer:

Explanation:

solve it urself idiot

7 0
2 years ago
10. Which is an example of mechanical energy?*
gtnhenbr [62]

Answer: A golfer hitting a golf ball.

Explanation:

The atomic particles move more in this option than the others.

6 0
3 years ago
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