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Nezavi [6.7K]
3 years ago
15

Although two identical objects may have the same mass and the same weight (meaning that the force of gravity is the same for bot

h), they may not fall to Earth at the same rate. This is because of air resistance. Any object that is falling has friction, or resistance, from the air. The larger the object, the more resistance it has as it falls.
Get two identical pieces of paper. Crumple one up into a ball, but leave the other one a flat sheet. Drop both pieces of paper off a high place at the same time. What happens? Which falls faster? Record your observations and make a conclusion, using the terms “mass,” “weight,” “force,” “resistance,” and “gravity.”

MUST BE AT LEAST 4 sentences and include the terms weight, force, resistance, and gravity.
Physics
1 answer:
andrew-mc [135]3 years ago
5 0

Answer:

the paper ball falls faster and the unfolded paper falls at a slower rate

Explanation:

this is because gravity is pulling both objects down to the ground and hence they are falling. Both objects have the same mass and weight but the resultant force of the paper ball is smaller than that of the unfolded paper. The unfolded paper has a larger surface area and so a larger force is acted upon it, meaning there is more air resistance. This shows that the paper ball falls faster than the unfolded paper.

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A car is driving at 85 km/h and the driver spots a stop sign ahead. What coefficient of friction is needed to stop the car at th
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Answer:

μ = 0.0315

Explanation:

Since the car moves on a horizontal surface, if we sum forces equal to zero on the Y-axis, we can determine the value of the normal force exerted by the ground on the vehicle. This force is equal to the weight of the cart (product of its mass by gravity)

N = m*g (1)

The friction force is equal to the product of the normal force by the coefficient of friction.

F = μ*N (2)

This way replacing 1 in 2, we have:

F = μ*m*g (2)

Using the theorem of work and energy, which tells us that the sum of the potential and kinetic energies and the work done on a body is equal to the final kinetic energy of the body. We can determine an equation that relates the frictional force to the initial speed of the carriage, so we will determine the coefficient of friction.

\frac{1}{2} *m*v_{i}^{2}-(F*d)=  \frac{1}{2} *m*v_{f}^{2}

where:

vf = final velocity = 0

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d = displacement = 900 [m]

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The final velocity is zero since when the vehicle has traveled 900 meters its velocity is zero.

Now replacing:

(1/2)*m*(23.61)^2 = μ*m*g*d

0.5*(23.61)^2 = μ*9,81*900

μ = 0.0315

5 0
3 years ago
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