Answer:
The quantity of energy per photon is inversely proportional to the wavelength of the light.
Explanation:
Energy of light is given as
E = hf
where E = energy of the photons,
f = frequency of the light
If the number of photons = n
(E/n) = (h/n) f
Let (E/n) = E'
(h/n) = h'
But the frequency of light is related to wavelength through the relation
v = fλ
where v = speed of light = c
λ = wavelength of light
f = (c/λ)
E' = h' f
Substituting for f
E' = h' (c/λ)
h' and c are both constants, h'×c = K
E' = (K/λ)
So, the quantity of energy per photon is inversely proportional to the wavelength of the light.
Hope this Helps!!!
If a particle undergoes simple harmonic motion with an amplitude of 0.21 meters, this means that the maximum displacement of the particle from its resting position is 0.21. For one period, it traveled from its starting position which is twice the amplitude and then back to its original position which is another distance that is twice the amplitude as well. Therefore, the total distance it traveled is 2*amplitude + 2*amplitude = 2*0.21 + 2*0.21 = 0.42 + 0.42 = 0.84 meters.
The answer is C radio waves are very high energy mechanical waves.
Answer:both are body waves often associated with seismic waves
Explanation:
Both are body waves often associated with seismic waves as in earthquakes
Answer:
q = 224 mm, h ’= - 98 mm, real imagen
Explanation:
For this exercise let's use the constructor equation
where f is the focal length, p and q are the distance to the object and the image respectively.
In a mirror the focal length is
f = R / 2
indicate us radius of curvature is equal to the diameter of the eye
R = 3,50 10² mm
f = 3.50 10² /2 = 1.75 10² mm
they also say that the distance to the object is p = 0.800 10³ mm
1 / q = 1 / f - 1 / p
1 / q = 1 / 175 - 1 /800
1 / q = 0.004464
q = 224 mm
to calculate the size let's use the magnification ratio
m = 
h '= 
h ’= - 224 350 / 800
h ’= - 98 mm
in concave mirrors the image is real.
