Question

3. A line goes through the points (3,4) and (-3,6).

Answer 1

Answer:

Part a) The slope is $m=-\frac{1}{3}$

Part b) The equation in point slope form is $y-4=-\frac{1}{3}(x-3)$

Part c) The equation in slope-intercept form is $y=-\frac{1}{3}x+5$

Step-by-step explanation:

we have the points (3,4) and (-3,6)

Part a) What is the slope of the line?

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the given points

$m=\frac{6-4}{-3-3}$

$m=\frac{2}{-6}$

$m=-\frac{1}{3}$

Part b) Write the equation of the line in point-slope form

$y-y1=m(x-x1)$

we have

$m=-\frac{1}{3}$

$point\ (3,4)$

substitute

$y-4=-\frac{1}{3}(x-3)$  ---> equation in point slope form

Part c) Write the equation of the line in slope-intercept form

$y=mx+b$

we have

$y-4=-\frac{1}{3}(x-3)$

Isolate the variable y

distribute right side

$y-4=-\frac{1}{3}x+1$

Adds 4 both sides

$y=-\frac{1}{3}x+1+4$

$y=-\frac{1}{3}x+5$ ---> equation in slope intercept form