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OLEGan [10]
3 years ago
13

g When a high-energy proton or pion traveling near the speed of light collides with a nucleus, it may travel 3.2 10-15 m before

interacting. From this information, find the time interval required for the strong interaction to occur.
Physics
1 answer:
AnnyKZ [126]3 years ago
5 0

Answer:

Time, t=1.07\times 10^{-23}\ s

Explanation:

Given that,

When a high-energy proton or pion traveling near the speed of light collides with a nucleus, it may travel 3.2\times 10^{-15}\ m before interacting.

Let t is the time interval required for the strong interaction to occur. It will move with the speed of light. So,

t=\dfrac{d}{c}\\\\t=\dfrac{3.2\times 10^{-15}}{3\times 10^8}\\\\t=1.07\times 10^{-23}\ s

So, the time interval is 1.07\times 10^{-23}\ s

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According to Kepler's Second Law the radius vector drawn from the Sun to a planet Multiple Choice is the same for all planets. s
Mademuasel [1]

Answer:

sweeps out equal areas in equal times.

Explanation:

As we know that there is no torque due to Sun on the planets revolving about the sun

so we will have

\tau_{net} = 0

now we have

\frac{dL}{dt}= 0

now we also know that

Area = \frac{1}{2}r^2d\theta

so rate of change in area is given as

\frac{dA}{dt} = \frac{1}{2}r^2\frac{d\theta}{dt}

so we will have

\frac{dA}{dt} = \frac{1}{2}r^2\omega

\frac{dA}{dt} = \frac{L}{2m}

since angular momentum and mass is constant here so

all planets sweeps out equal areas in equal times.

4 0
3 years ago
What is the force required to move a block of mass 150 pound by a distance of 5ft in 8 seconds?
Nadusha1986 [10]

Force required to move a block is 1.615 N

Given:

mass of block = m = 150 pounds = 68 kg

distance = d = 5 ft = 1.52 metres

time = t = 8 sec

To Find:

force required to move the block

Solution: Force is defined as product of mass and acceleration and it's unit is N or Newton.

Velocity = displacement/ time = 1.52 / 8 = 0.19 m/s

Acceleration = velocity/time = 0.19/8 =

0.023 m/s^2

Force = mass x acceleration = 68x0.023 = 1.615 N

Hence, force required to move the block is 1.615 N

Learn more about Force here:

brainly.com/question/12970081

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8 0
2 years ago
What is the unit for force?
Morgarella [4.7K]

Answer:

N / NEWTONS

Explanation:

Named after Isaac Newton, the man who discovered gravity

3 0
3 years ago
Read 2 more answers
A box sliding on a horizontal frictionless surface runs into a fixed spring, compressing it a distance x1 from its relaxed posit
inn [45]

Answer:twice of initial value

Explanation:

Given

spring compresses x_1 distance for some initial speed

Suppose v is the initial speed and k be the spring constant

Applying conservation of energy

kinetic energy converted into spring Elastic potential energy

\dfrac{1}{2}mv^2=\dfrac{1}{2}kx_1^2----1

When speed doubles

\dfrac{1}{2}m(2v)^2=\dfrac{1}{2}kx_2^2----2

divide 1 and 2

\dfrac{1}{4}=\dfrac{x_1^2}{x_2^2}

x_2=2x_1

Therefore spring compresses twice the initial value

   

7 0
3 years ago
A block of mass 1.5 hangs at the of end of a weight cord suspended from the ceiling.what is the tension in the cord, and with wh
Len [333]

The tension in the cord is 14.7 N and the force of pull of the cord is 14.7 N, assuming the block is stationary.

<h3>What is the tension in the cord?</h3>

The tension in the cord is calculated as follows;

T = ma + mg

where;

  • a is the acceleration of the block
  • g is acceleration due to gravity
  • m is mass of the block

T = m(a + g)

T = 1.5(a + 9.8)

T = 1.5a + 14.7

Thus, the tension in the cord is (1.5a + 14.7) N.

If the block is at rest, the tension is 14.7 N.

<h3>Force of the force</h3>

The force with which the cord pulls is equal to the tension in the cord

F = T = m(a + g)

F = (1.5a + 14.7) N

If the block is stationary, a = 0, the tension and force of pull of the cord = 14.7 N.

Thus, the tension in the cord is 14.7 N and the force of pull of the cord is 14.7 N, assuming the block is stationary.

Learn more about tension here: brainly.com/question/187404

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4 0
1 year ago
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