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Kay [80]
4 years ago
7

How many significant figures are in 20600?

Chemistry
1 answer:
-BARSIC- [3]4 years ago
6 0

There are 3 significant figures in 20600.

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A galvanic cell whose cell reaction is 2Fe3+(aq) + Zn(s) → 2Fe2+(aq) + Zn2+(aq) has a cell potential of 0.72V. What is the maxim
sesenic [268]

Answer:

138.96kJ is the maximum electrical work

Explanation:

The maximum electrical work that can be obtained from a cell is obtained from the equation:

W = -nFE

<em>Where W is work in Joules,</em>

<em>n are moles of electrons = 2mol e- because half-reaction of Zn is:</em>

Zn(s) → Zn²⁺(aq) + 2e⁻

F is faraday constant = 96500Coulombs/mol

E is cell potential = 0.72V

Replacing:

W = -2mol*96500Coulombs/mol*0.72V

W = - 138960J =

<h3>138.96kJ is the maximum electrical work</h3>

<em />

5 0
3 years ago
The development of a nuclear power plant at an ocean site is expected to produce an enormous amount of electric power for a larg
Oksanka [162]

Answer:

B. The effects of warmed water on aquatic life

Explanation:

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8 0
3 years ago
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To show the electron configuration for an atom, when would it be better to use an orbital notation than to use a written configu
Kisachek [45]
The answer is: when the aim is to show electron distributions in shells

An orbital notation is more appropriate if you want to show how the electrons of an atom are distributed in each subshell. This is because there are some atoms that have special electronic configurations that aren't obvious in just written configurations.
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What does fossil mean in my own words
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Answer: A thing that died a long time ago, and it's bones were preserved in the ground.

Explanation:

Because yes

6 0
4 years ago
Describe a method to calculate the average atomic mass of the sample in the previous question using only the atomic masses of li
alexira [117]

Answer:

Explanation:

To calculate their average atomic masses which is otherwise known as the relative atomic mass, we simply multiply the given abundances of the atoms and the given atomic masses.

The abundace is the proportion or percentage or fraction by which each of the isotopes of an element occurs in nature.

This can be expressed below:

        RAM = Σmₙαₙ

where mₙ is the mass of isotope n

           αₙ is the abundance of isotope n

for this problem:

RAM of Li = m₆α₆ + m₇α₇

       m₆ is mass of isotope Li-6

        α₆ is the abundance of isotope Li-6

       m₇ is mass of isotope Li-7

        α₇ is the abundance of isotope Li-7

3 0
4 years ago
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