It can be transmit in hydraulic machine, exerting a small cross-sectional area can lead to pressure being transmitted
<span>if we assume the origin is at the dropping point and the object is merely dropped and not thrown up or down then y0 = 0 and v0 = 0. The equation reduces to </span>
<span>y = 0 + 0t + ½gt² </span>
<span>y = ½gt² </span>
<span>t = √(2y/g) </span>
<span>in the ft - lb - s system </span>
<span>y = -100 ft </span>
<span>g = -32.2 ft / s² </span>
<span>t = √(2y/g) </span>
<span>t = √(2(-100) / (-32.2)) </span>
<span>t = 2.5 s</span>
Answer:
i want to say flip the coins but im not really sure sry
Explanation:
<u>Answer:</u>
<em>Thunderbird is 995.157 meters behind the Mercedes</em>
<u>Explanation:</u>
It is given that all the cars were moving at a speed of 71 m/s when the driver of Thunderbird decided to take a pit stop and slows down for 250 m. She spent 5 seconds in the pit stop.
Here final velocity 
initial velocity
distance
Distance covered in the slowing down phase = 







The car is in the pit stop for 5s 
After restart it accelerates for 350 m to reach the earlier velocity 71 m/s





total time= 
Distance covered by the Mercedes Benz during this time is given by 
Distance covered by the Thunderbird during this time=
Difference between distance covered by the Mercedes and Thunderbird
= 
Thus the Mercedes is 995.157 m ahead of the Thunderbird.