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Ivenika [448]
3 years ago
7

A large piece of jewelry has a mass of 130.8 g. A graduated cylinder initially contains 47.7 mL water. When the jewelry is subme

rged in the graduated cylinder, the total volume increases to 62.4 mL. (a) Determine the density (in g/cm3) of this piece of jewelry. g/cm3
Physics
1 answer:
Shkiper50 [21]3 years ago
8 0

Answer: The density of this piece of jewelry is 8.90g/cm^3

Explanation:

To calculate the density, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Mass of piece of jewellery = 130.8 g

Density of piece of jewellery = ?

Volume of piece of jewellery =( 62.4-47.7 ) ml = 14.7 ml = 14.7cm^3   1cm^3=1ml

Putting values in above equation, we get:

\text{Density of piece of jewellery}=\frac{130.8g}{14.7cm^3}=8.90g/cm^3

Thus density of this piece of jewelry is 8.90g/cm^3

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Who is responsible of refraction light 1/3 in eye
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3 0
2 years ago
A truck traveling at a velocity of 33m/s comes to a halt by decelerating at 11m/s^2. How far does the truck travel in the proces
snow_lady [41]

Answer:

<u><em>The truck was moving 16.5 m/s during the time it took to stop, which was 3 seconds. </em></u>

  • <u><em>Initial velocity = 33 m/s</em></u>
  • <u><em>Final velocity = 0 m/s</em></u>
  • <u><em>Average velocity = (33 + 0) / 2  m/s = 16.5 m/s</em></u>

Explanation:

  1. <u><em>First, how long does it take the truck to come to a complete stop?</em></u>
  1. <u><em>( 33 m/s ) / ( 11 m / s^2 ) = 3 seconds</em></u>
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4 0
3 years ago
2
luda_lava [24]

Answer:

500000N/m²

5250N

Explanation:

Given parameters:

Depth(H) = 50m

Density of water  = 1000kg/m³

Acceleration of free fall  = 10m/s

Unknown:

Pressure the water exerts on the diver = ?

Solution:

Pressure is the force per unit area on a body. In fluids, pressure is the product of density, gravity and height

  Pressure in fluids  = Density x acceleration due to gravity x height

Input the variables and solve;

    Pressure in fluids  = 1000 x 10 x 50  = 500000N/m²

B.

width of window = 150mm

height of window = 70mm

Force water exerts on the window = ?

To solve this problem;

         Pressure  = \frac{Force}{Area}

Area of the window = width x height  = 150 x 10⁻³ x 70 x 10⁻³

                                                           = 1.05 x 10 ⁻²m²

Force  = pressure x area

Input the variables;

             = 500000N/m²   x  1.05 x 10 ⁻²m²

             = 5250N

4 0
3 years ago
Helppppppppppppppppppppppppp
andrew11 [14]

Answer:

value of x=35°

y=72.5°

hope it helps you

make me brainliest plz

6 0
3 years ago
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