Well, the reason behind this is because water depth (I assume you're talking about water/liquid) increases the pressure because of the weight and volume of the water above. I hope this helps! ~Mia
Answer:
Fy=107.2 N
Explanation:
Conceptual analysis
For a right triangle :
sinβ = y/h formula (1)
cosβ = x/h formula (2)
x: side adjacent to the β angle
y: opposite side of the β angle
h: hypotenuse
Known data
h = T = 153.8 N : rope tension
β= 44.2°with the horizontal (x)
Problem development
We apply the formula (1) to calculate Ty : vertical component of the rope force.
sin44.2° = Ty/153.8 N
Ty = (153.8 N ) *(sen44.2°)= 107.2 N directed down
for equilibrium system
Fy= Ty=107.2 N
Fy=107.2 N upward component of the force acting on the stake
Answer:
4462.0927 W
Explanation:
= Emissivity of the panel = 1
= Stefan-Boltzmann constant = ![5.67\times 10^{-8}\ W/m^2K^4](https://tex.z-dn.net/?f=5.67%5Ctimes%2010%5E%7B-8%7D%5C%20W%2Fm%5E2K%5E4)
T = Temperature = (273.15+6)
Area of the panel is given by
![A=2\times 1.8\times 3.6\\\Rightarrow A=12.96\ m^2](https://tex.z-dn.net/?f=A%3D2%5Ctimes%201.8%5Ctimes%203.6%5C%5C%5CRightarrow%20A%3D12.96%5C%20m%5E2)
The power radiated is given by
![P=\epsilon \sigma AT^4\\\Rightarrow P=1\times 5.67\times 10^{-8}\times 12.96\times (273.15+6)^4\\\Rightarrow P=4462.0927\ W](https://tex.z-dn.net/?f=P%3D%5Cepsilon%20%5Csigma%20AT%5E4%5C%5C%5CRightarrow%20P%3D1%5Ctimes%205.67%5Ctimes%2010%5E%7B-8%7D%5Ctimes%2012.96%5Ctimes%20%28273.15%2B6%29%5E4%5C%5C%5CRightarrow%20P%3D4462.0927%5C%20W)
The power radiated from each panel is 4462.0927 W