Question

A rifle with a weight of 40 N fires a 5.5-g bullet with a speed of 220 m/s.(a) Find the recoil speed of the rifle.

Answer 1

Answer:

0.2695/s

Explanation:

Using the formula for calculating impulse

Impulse = m(v-u) = Ft

M is the mass

v is the final velocity.

u is the initial velocity

F is the force

t is the time

Get the time;

t = m(v-u)/F

t = 0.0055(220)/40

t = 0.0275s

Get the speed of the rifle

v = u+gt.

v = 0+9.8(0.0275).

v = 0.2695m/s

Hence the speed of the rifle is 0.2695m/s