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3 years ago

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Solve 6x+ c = k for x. O A. x-kom O B. x= 6(k+ c) O c. x-kt0 O D. x= 6(k-c)

1 answer:

erastova [34]3 years ago

7 0

Step-by-step explanation:

6x+c = k

=> 6x = k-c

=> x = (k-c)/6

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Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms

miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

Break the given sequence into two parts .
Notice the terms at gap of one term beginning from the first term .They are like $\dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ . Next term is obtained by multiplying half to the previous term .
Notice the terms beginning from 2nd term , $4,7,10,13$ . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

$\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

$\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]$

Notice the term $\dfrac{1}{2^{25}}$ will be too small , so we can neglect it and take its approximation as 0 .

$\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]$

$\\\implies \boxed{ S_1 \approx 1 }$

$\rule{200}2$

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

$\implies S_2=\dfrac{n}{2}[2a + (n-1)d]$

Substitute ,

$\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}$

Hence sum = 908 + 1 = 909

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3 years ago

The largest possible circle is cut out of a square whose side length is 8 feet. What will be the approximate area, in square fee

Lunna [17]

Answer:

=13.73 ft²

Step-by-step explanation:

The diameter of the largest possible circle that can be cut out of a square is equal to the length of the side of the square.

Therefore the diameter of the circle cut from a square of side 8ft =8ft

r=4ft

Area of the remaining board= Area of square- area of circle

=side²-πr²

=8²-π×4²

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if a tree 20 meters tall casts a shadow 30 meters long, what is the angle of elevation from the shadow to the tip of the tree, t

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sketch the situation

a trigonometric function that is a relation between the angle of elevation and the 2 sides of the rectangles is the tan

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find the inverse

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after rounding the angle of elevation is 34º.

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