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2 years ago

10

Susan goes out to exercise. She runs for one hour at a constant speed and velocity. What is the overall net force acting on Susa

n?

2 answers:

umka21 [38]2 years ago

7 0

Well since there is no acceleration..the net force is zero

Roman55 [17]2 years ago

3 0

<span>The net force acting on the runner must be zero.</span>

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The California sea lion is capable of making extremely fast, tight turns while swimming underwater. In one study, scientists obs

anygoal [31]

Answer:

Acceleration of Sea Lion is 4.41 g

This is 49% of maximum jet acceleration given as a = 9g

Explanation:

As we know that the radius of the circular loop is given as

R = 0.37 m

The speed of the fish is given as

$v = 4 m/s$

Now the centripetal acceleration of the sea lion is given as

$a_c = \frac{v^2}{R}$

$a_c = \frac{4^2}{0.37}$

$a_c = 43.2 m/s^2$

as we know that

$g = 9.8 m/s^2$

so we have

$a = 4.41 g$

Now Percentage of this acceleration wrt maximum jet acceleration is given as

$P = \frac{4.41 g}{9g} \times 100$

$P = 49$ %

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2 years ago

Since the Sun has more mass, why do objects on earth not move closer to the Sun instead of staying put on Earth?

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Answer:

Because the Earth has it's own gravity that keeps us put, and we also have the moon.

Explanation:

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2 years ago

Which portion of the electromagnetic spectrum is used in a microscope?

erik [133]

Answer is C.

Optical microscope involves passing visible light transmitted through or reflected from the sample through a single or multiple lenses to allow a magnified view of the sample.

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2 years ago

After asking a question, a scientist can form a(n) , which is an idea that may be proved or disproved by an experiment.

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Answer:

When scientists have a question, they form a hypothesis, <em>which</em><em> </em><em>is</em><em> </em><em>an</em><em> </em><em>idea</em><em> </em><em>that</em><em> </em><em>may</em><em> </em><em>be</em><em> </em><em>proved</em><em> </em><em>or</em><em> </em><em>disproved</em><em> </em><em>by</em><em> </em><em>an</em><em> </em><em>experiment</em><em>.</em>

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2 years ago

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If the distance between slits on a diffraction grating is 0.50 mm and one of the angles of diffraction is 0.25°, how large is th

Trava [24]

Answer:

- path differnce = 2.18*10^-6

- 1538 lines

Explanation:

- The path difference for the waves that produce the pattern of diffraction, is given by the following formula:

$path\ difference\ = dsin\theta$ (1)

d: separation between slits = 0.50mm = 0.50*10^-3 m

θ: angle of a diffraction = 0.25°

Then, the path difference is:

$path\ difference\ =(0.50*10^{-3}m)sin(0.25\°)=2.18*10^{-6}m$

- The maximum number of bright lines are calculated by using the following formula:

$m\lambda = dsin\theta$ (2)

m: order of the bright

λ: wavelength = 650nm

The maximum bright is calculated for an angle of 90°:

$m=\frac{(0.50*10^{-3}m)sin90\°}{650*10^{-9}m} \approx 769$

The maxium number of bright lines are twice the previous result, that is, 1538 lines

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2 years ago

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