There’s a first
“clump”/drum beat every half second. That clump will travel about 170m in half
a second. Someone 170m away would do their “clump” as the second “clump” was
taking place. I think. <span>
</span>
Answer:
La velocidad media es 5 
, que equivale a 1.389 
Explanation:
La velocidad es una magnitud física que expresa la relación entre el espacio recorrido por un objeto y el tiempo empleado para ello.
La velocidad media relaciona el cambio de la posición con el tiempo empleado en efectuar dicho cambio. Por lo que se calcula como la distancia recorrida por un objeto dividido por el tiempo transcurrido:
En este caso:
- distancia= 10 km= 10,000 m (siendo 1 km= 1,000 m)
- tiempo= 2 h= 7,200 s (siendo 1 h= 3,600 s)
Entonces, reemplazando en la definición de velocidad media:
Resolviendo se obtiene:
<u><em>La velocidad media es 5 </em></u><u><em>, que equivale a 1.389 </em></u><u><em></em></u>
Answer:
option (a)
Explanation:
the angular velocity of the carousel is same througout the motion, so the angular velocity of all the horses is same, but the linear velocity is different for different horses.
As the angular displacement of all the horses are same in the same time so the angular velocity is same.
The relation between the linear velocity and the angular velocity is given by
v = r ω
where, v is linear velocity and r be the distance between the horse and axis of rotation and ω be the angular velocity.
So, the angular velocity of Alice horse is same as the angular velocity of Bob horse.
ωA = ωB
Thus, option (a) is true.
Answer: Macroscoptic Output
Explanation:
Answers to the rest:
1. B) macroscopic outputs.
2.A) a microscopic change creating a macroscopic output
3.B) Because the energy levels of the electrons in different metals are usually not the same, different metals usually emit different colors of visible light.
4.A) Heat is applied to a solid, causing its molecules to move quickly.
5.A) strontium, sodium, copper, potassium
A ) v = v o - a t
0 = 22 - a · t
a · t = 22
d = v o · t - a t²/2
0.04 = 22 t - 22 t / 2
0.04 = 11 t
t = 0.04 : 11 = 0.003636 s
a = 22 / t
a = 6050 m/s²
F = m · a = 0.09 kg · 6050 m/s²
F ( target→arrow) = - 544.5 N
b ) F ( arrow→target ) = 544.5 N
c ) If the speed was doubled: v = 44 m/s;
F = a m
a = 6050 m/s²
a · t = 44
t = 6050 : 0.04
t = 0.007272 s
d = 44 t - 44 t/2 = 22 t
d = 22 · 0.007272
d = 0.16 m = 16 cm
