3 years ago

You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 2.1 m/s. The

Physics

1 answer:

garri49 [273]3 years ago

7 0

Answer:

4.6 Joules

Explanation:

K=1/2*MV^2

1/2 * 2.1kg * 2.1^2m/s

==4.6305 Joules

simplified to 4.6 Joules

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A crate with a mass of m = 450 kg rests on the horizontal deck of a ship. The coefficient of static friction between the crate a

Zielflug [23.3K]

Answer: $F_{v} =\mu_{k} mg$

Magnitude of the force is 2601.9 N

Explanation:

m = 450 kg

coefficient of static friction μs = 0.73

coefficient of kinetic friction is μk = 0.59

The force required to start crate moving is $F_{s} =\mu_{s} mg$ .

but once crate starts moving the force of friction is reduced $F_{v} =\mu_{k} mg$ .

Hence to keep crate moving at constant velocity we have to reduce the force pushing crate ie $F_{v} =\mu_{k} mg$ .

Then the above pushing force will equal the frictional force due to kinetic friction and constant velocity is possible as forces are balanced.

Magnitude of the force

$F_{v} =\mu_{k} mg\\F_{v} =0.59 \times 450 \times 9.8\\F_{v} =2601.9 N$

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3 years ago

How is item A different from Item B?

iris [78.8K]

Explanation:

well there is nothing there and it could be different by diffrent objects, idk

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3 years ago

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A drag racer starts from the rest and accelerates at 7.4m/s^2.how far will he travel in 2.0 seconds?

Vesna [10]

Answer:

14.8 m

Explanation:

S= ut + $\frac{1}{2}$ a $t^{2}$

where u = initial velocity

S= (0 $\frac{m}{s}$ )(2 $s$ ) + $\frac{1}{2}$ (7.4 $\frac{m}{s^{2} }$ )(2 $s^{2}$ )

S= $\frac{1}{2}$ (7.4 $\frac{m}{s^{2} }$ )(2 $s^{2}$ )

S=14.8 m

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3 years ago

10.A car is travelling at a constant speed of 27m/s. The driver looks away from the road for a 2.0s to tune in a station on the

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Explanation:

Distance = speed × time

d = (27 m/s) (2.0 s)

d = 54 m

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3 years ago

Explain the characteristics of the Gypsum Hills regionIf we have a sample of silicon (Si) atoms that has 14 protons, 14 electron

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Answer:

second one

Explanation:

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