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Readme [11.4K]
3 years ago
15

How is "food" produced in ecosystems without sunlight?

Chemistry
2 answers:
NeX [460]3 years ago
5 0

Answer:

A Chemosynthesis

Explanation:

lisabon 2012 [21]3 years ago
4 0
The answer would be A. By chemosynthesis
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How many photons are contained in a burst of yellow light (589 nm) from a sodium lamp that contains 623 kJ of energy?
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<span>First we need to find the energy of one photon with a wavelength of 589 nm. E = hc / wavelength E = (6.63 x 10^{-34} J s)(3 x 10^8 m/s) / (589 x 10^{-9} m) E = 3.3769 x 10^{-19} Joules To find N, the number of photons, we need to divide the total energy by the energy of each photon. N = 623000 J / 3.3769 x 10^{-19} Joules N = 1.84 x 10^{24} photons There are 1.84 x 10^{24} photons in the burst of yellow light.</span>
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3 years ago
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3 years ago
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Scoring Scheme: 3-3-2-1 Part I. How many mL of 6 M NaOH stock solution should be used to prepare the 500 mL of 0.2 M NaOH? Pleas
Orlov [11]

Answer : The volume of 6M NaOH stock solution is, 16.7 mL

Explanation :

To calculate the volume of NaOH stock solution, we use the equation given by neutralization reaction:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of NaOH stock solution.

M_2\text{ and }V_2 are the molarity and volume of NaOH.

We are given:

M_1=6M\\V_1=?\\M_2=0.2M\\V_2=500mL

Putting values in above equation, we get:

6M\times V_1=0.2M\times 500mL\\\\V_1=16.7mL

Thus, the volume of 6M NaOH stock solution is, 16.7 mL

4 0
4 years ago
A reaction has ∆H = −356 kJ and ∆S = −36 J/K. Calculate ∆G (kJ) at 25°C.
Cloud [144]

Answer: -345.2 KJ

Explanation: As we know that ,dG=dH-TdS

T=25+273=298 K

dG= -356 x1000-298(-36)= -356000+10728

=-345272 j

= -345.2 KJ

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3 years ago
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Answer:

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