1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Readme [11.4K]
3 years ago
15

How is "food" produced in ecosystems without sunlight?

Chemistry
2 answers:
NeX [460]3 years ago
5 0

Answer:

A Chemosynthesis

Explanation:

lisabon 2012 [21]3 years ago
4 0
The answer would be A. By chemosynthesis
You might be interested in
Using the van der waals equation, the pressure in a 22.4 l vessel containing 1.50 mol of chlorine gas at 0.00 °c is ________ atm
Lana71 [14]

Answer is: the pressure in a vessel is 1.48 atm.

V(Cl₂) = 22.4 L; pressure of chlorine gas.

n(Cl₂) = 1.50 mol; amount of chlorine gas.

T = 0.00°C = 273.15 K; temperature.

a = 6.49 L²·atm/mol²; the constant a provides a correction for the intermolecular forces.

b = 0.0562 L/mol; value is the volume of one mole of the chlorine gas.

R = 0.08206 L·atm/mol·K, universal gas constant.

Van de Waals equation: (P + an² / V²)(V - nb) = nRT.

(P +  6.49 L²·atm/mol² · (1.5 mol)² / (22.4 L)²) · (22.4 L - 1.5 mol·0.0562 L/mol) = 1.5 mol · 0.08206 L·atm/mol·K · 273.15 K.

(P +  6.49 L²·atm/mol² · (1.5 mol)² / (22.4 L)²) = (1.5 mol · 0.08206 L·atm/mol·K · 273.15 K) ÷ (22.4 L - 1.5 mol · 0.0562 L/mol).

P + 0.029 atm = 33.62 L·atm ÷ 22.31 L.

P = 1.507 atm - 0.029 atm.

P = 1.48 atm; the pressure.

7 0
3 years ago
50 POINTS!!!!!!
sattari [20]
Remember that enzymes always accelerate chemical equations, depending on what the enzyme is consisted of. As the enzymes are burned the reaction or amount of chemical reactions decreases.
4 0
3 years ago
How to make vape oil from scratch for a vape pen
Julli [10]
If you’ve been vaping for a while now, you may be craving some new vape juice flavors to try with your favorite RDA, RTA, or Box Mod.

You might find that ordering large batches of your all day vape juice flavors can prove a bit on the expensive side, particularly if your tastes run toward the premium e juice priced at over $20 per bottle.

Surely there must be a better way than taking out payday loans to get your hands on that Peanut Butter Crunch-flavored creation you just have to have in your sub-ohm tank?

Fortunately, when you know how to make homemade vape juice it can be a fun and fascinating hobby that has the delightful side effect of saving you loads of cash using cheap vape juice.

Many people hear “diy vape juice” and get visions of a mad scientist in a dank lab constantly flirting with explosion by mixing volatile chemicals while laughing insanely.

The reality is that it’s relatively easy to learn how to make your own vape juice at home, and we’re going to attempt to cover all the facets involved.

Are you interested in making your own e juice?
3 0
4 years ago
Read 2 more answers
What is the filtrate?
kondaur [170]

Answer:

a liquid which has passed through a filter.

Explanation:

Filtration is a physical separation process that separates solid matter and fluid from a mixture using a filter medium that has a complex structure through which only the fluid can pass

5 0
2 years ago
The fire department needs information on friction losses occurring between a water main and an open fire hydrant. At maximum mai
lisov135 [29]

Explanation:

The given data is as follows.

      P_{1} = 85 psig,   P_{2} = P_{atm} = 15 psia

        Q = 1620 gpm,  d = 2.5 inch,     l = 8 ft = 2.4384 m

According to Darey-Weisbach equation,

                        h_{l} = \frac{4fl \nu^{2}}{2gD}  ......... (1)

Value of 'f' will be decided on the basis of Reynold number.

As, it is known that R_{l} = \frac{\rho \nu d}{\mu}

where,  \mu_{water} = 10^{-3} kg/ms

As it is known that 1 gpm = \frac{1}{3.67} m^{3}/hr

So,  1 m^{3}/hr = 3.67 gpm

Therefore,   Q = 1620 \times \frac{1}{3.67}

                        = 441.4168 m^{3}/hr

                         = 0.1226 m^{3}/s

In, 1 inch = 2.54 cm = 0.0254 m

Therefore, d = 2.5 \times 0.0254 = 0.0635 m

                V = \frac{Q}{\frac{\pi}{4}d^{2}}

                    = \frac{0.1226}{0.785 \times (0.0635)^{2}}

                    = 38.73 m/s

Hence, we will calculate Reynold number as follows.

             R_{l} = \frac{1000 \times 38.73 \times 0.0635}{10^{-3}}

                             = 2459355

As R_{l} > 2000 then, it means that flow is turbulent.

As, f = 0.079 R^{-0.25}_{l}

        = 0.001994

Putting all the values into equation (1) formula as follows.    

                          h_{l} = \frac{4fl \nu^{2}}{2gD}

                                     = \frac{4 \times 0.001994 \times 2.4384 \times (38.73)^{2}}{2 \times 9.81 \times 0.0635}

                                      = 1.04069 \times 10^{5} m

Thus, we can conclude that friction loss from the main to the discharge point is 1.04069 \times 10^{5} m.

4 0
3 years ago
Other questions:
  • What is the correct complimentary strand for the following DNA?ATCGAG
    10·1 answer
  • Which of these is not an example of energy being converted from one form into another form?
    6·1 answer
  • A household receives a $146 electricity bill. The cost of electricity is $0.129/kWh. How much energy, in joules, did the househo
    13·1 answer
  • A type of energy that is stored is called?
    6·1 answer
  • 1. For one atom of lithium -6 I will need_____ atom of lithium -7 for an average atomic mass of 6.944? 2. For one atom of lithiu
    11·1 answer
  • A catalyst lowers the activation energy of a reaction by
    10·1 answer
  • Which of these is a chemical property?
    7·1 answer
  • Decide whether a chemical reaction happens in either of the following situations. If a reaction does happen, write the chemical
    15·1 answer
  • Describe nucleus of atom​
    6·2 answers
  • Click Reset and drop object A back into the water. About what percentage of object A is under the water? How is this percentage
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!