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Thepotemich [5.8K]
3 years ago
11

what is the point slope form of an equation with the slope of 3/5 that passes through the point (10,-2)?

Mathematics
1 answer:
Mama L [17]3 years ago
6 0
Point slope form of a line:
y-y_1=m(x-x_1) where m is your slope and (x_1,\ y_1) is a point on your line.

For a line with a slope of 3/5 that passes through (10, -2)...
m=\frac35,\ x_1=10,\ y_1=-2
Let's plug these values into our formula.

y-(-2)=\frac35(x-10)

Subtracting by a negative is the same thing as adding (the double negatives cancel), so let's simplify that.

\boxed{y+2=\frac35(x-10)}

There's our equation in point-slope form. (keep in mind that you're not going to want to distribute that 3/5 or subtract the 2 or anything. You want to keep it similar to the formula.
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4 0
3 years ago
What is the area of the trapezoid?
Alecsey [184]

Area of trapezoid:

A = 1/2(b1+b2)h

where

b1 = 30,

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Triangle FOG

a^2 = c^2 - b^2

a^2 = 13^2 - 12^2

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a = √25

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FO = 5 so height h = FO = 5

Now you can find the Area of trapezoid

A = 1/2(b1+b2)h

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Answer

175 square units

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