Question

A sailor pulls a boat horizontally along a dock for 10.0 m with an angled rope. He does 766 J of work and has a force of 100.0 N. What was the angle of the rope?
O 40°

Answer 1

Explanation:

W = Fd cos θ

766 J = (100.0 N) (10.0 m) cos θ

cos θ = 0.766

θ = 40.0°