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Delvig [45]
3 years ago
6

Significant Figures: How many significant figures are in 865,010?

Chemistry
1 answer:
Harrizon [31]3 years ago
7 0

Answer: There are five significant figures in 865,010.

Explanation:

When a degree of accuracy is stated by each digit present in a mathematical figure then it is called a significant figure.

Rules for counting significant figures is as follows.

  • Any non-zero digits and zeros present between a non-zero figure are counted. For example, 3580009 has seven significant figures.
  • Trailing zeros are counted in a non-zero figure. For example, 0.00250 has three significant figures.
  • Leading zeros are not counted. For example, 0.0025 has two significant figures.

So, in the given figure 865010 has five significant figures and the trailing zero will not be counted.

Thus, we can conclude that there are five significant figures in 865,010.

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What best describes charles law
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A) If volume increases, temperature increases

The law is V/T, meaning the two values are directly proportional, as one increases, the other increases too.

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What weight of sodium nitrate (NaNO3) must be used to prepare 506mL of a 10.5 M solution of this salt in water? Answer in units
topjm [15]

The question requires us to calculate the mass of NaNO3 necessary to prepare 506 mL of a 10.5 M solution of this salt.

To answer this question, we'll need to go through the following steps:

1) Calculate the molar mass of NaNO3, as it will be necessary during the question;

2) Calculate the number of moles necessary to prepare 506 mL of the 10.5 M solution;

3) Convert the number of moles calculated into the mass of NaNO3, using the molar mass of this salt.

Next, we'll follow the steps:

1) To calculate the molar mass of NaNO3, we need to consider the atomic masses of Na, N and O and the number of atoms of each of these elements. The atomic masses are 22.99 u, 14.01 u and 15.99 u for Na, N and O, respectively. With this information, we can calculate the molar mass:

molar mass of NaNO3 = (1 * 22.99) + (1 * 14.01) + (3 * 15.99) = 84.97 g/mol

2) Next, we use the molar concentration provided (10.5 M or 10.5 mol/L) and the volume required (506 mL = 0.506 L) to obtain the number of moles necessary to prepare this solution:

<em>1 L of solution --------------- 10.5 mol of NaNO3</em>

<em>0.506 L of solution -------- x</em>

Solving for x, we have:

x=\frac{(0.506\text{ L of solution)}\times(10.5\text{ mol of NaNO}_3)}{(1\text{ L of solution)}}=5.31\text{ mol of NaNO}_3

Therefore, the number of moles of NaNO3 necessary to prepare the solution is 5.31 moles.

3) At last, we use the molar mass obtained in step 1 (84.97 g/mol) to calculate the mass that corresponds to 5.31 moles of NaNO3:

<em>1 mol of NaNO3 ---------------- 84.97 g</em>

<em>5.31 mol of NaNO3 ----------- y</em>

Solving for y, we have:

y=\frac{(5.31\text{ mol of NaNO}_3)\times(84.97\text{ g of NaNO}_3)}{(1\text{ mol of NaNO}_3)}=451.2\text{ g of NaNO}_3

Therefore, the mass of NaNO3 necessary to prepare the solution given by the question is 451.2 g.

6 0
1 year ago
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brainly.com/question/28168442

#SPJ4

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3. Visual communication utilizes drawings, illustrations, pictures, colors, graphs, charts, and signs to share meaning.

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