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Sloan [31]
3 years ago
14

In comparison with other ocean basins, major sedimentary features such as continental rises and abyssal plains are relatively ra

re in the Pacific. The primary reason for their scarcity in the Pacific is that __________.
Physics
1 answer:
Maksim231197 [3]3 years ago
3 0

Answer:

Why are continental rises and abyssal plains relatively rare in the Pacific? This is because the extensive system of trenches along the active margins of the Pacific, trap much of the sediments flowing off the continents, preventing them from building the broad, flat abyssal plains typical of the Atlantic ocean basins.

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V125BC [204]
The resultant force is 3 N north.
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What is a disadvantage of using biomass as an energy resource?
Rama09 [41]

Answer:

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The Sun is about 150 million km from earth. how long does it take light from the sun to reach earth? (Speed of light is 3x10^8m/
madam [21]

Time  =        (distance) / (speed)

Time  =  (150 x 10⁹ m) / (3 x 10⁸ m/s) =

                           50 x 10¹ sec  = 

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3 0
4 years ago
A balloon-powered car rolls across the floor at a speed of 0.711 m/s. How long does it take to cover 8.25 m?
devlian [24]

Answer:

Time = 11.60 seconds.

Explanation:

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the equation;

Speed = \frac{distance}{time}

Given the following data;

Speed = 0.711m/s

Distance = 8.25m

To find the time;

Making time the subject of formula, we have;

Time = \frac{distance}{speed}

Substituting into the equation, we have;

Time = \frac{8.25}{0.711}

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5 0
3 years ago
You push on a cart (18.0kg) at a 30 degree below horizontal angle. The coefficient of kinetic friction between the chair and the
podryga [215]

Given that force is applied at an angle of 30 degree below the horizontal

So let say force applied if F

now its two components are given as

F_x = Fcos30


F_y = Fsin30


Now the normal force on the block is given as

N = Fsin30 + mg

N = 0.5F + (18\times 9.8)

N = 0.5F + 176.4

now the friction force on the cart is given as

F_f = \mu N

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F_f = 110.25 + 0.3125F

now if cart moves with constant speed then net force on cart must be zero

so now we have

F_f + F_x = 0

Fcos30 - (110.25 + 0.3125F) = 0

0.866F - 0.3125F = 110.25

F = 199.2 N

so the force must be 199.2 N

8 0
3 years ago
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