Answer:10842.33m/s
Explanation:
F=qvBsine
V=f/(qBsine)
V=(3.5×10^-2)÷(8.4×10^-4×6.7×10^-3×sin35)
V=10842.33m/s
Sorry bro I just need points for my calculus exam
Answer: 
Explanation:
Given
Radioactive material is found to decrease 40% of its original value in 
Sample at any time is given by

where, 
Put values

Taking natural logarithm both side

As a system is cooled to its freezing point, the kinetic energy of the particles in the system will lower so the movement are much slower. Cooling means taking out heat from the system. This process is a physical change because it is only the phase of the system is changed and it is still the substance after the process.
Answer:
The tunnel probability for 0.5 nm and 1.00 nm are
and
respectively.
Explanation:
Given that,
Energy E = 2 eV
Barrier V₀= 5.0 eV
Width = 1.00 nm
We need to calculate the value of 
Using formula of 

Put the value into the formula


(a). We need to calculate the tunnel probability for width 0.5 nm
Using formula of tunnel barrier

Put the value into the formula


(b). We need to calculate the tunnel probability for width 1.00 nm


Hence, The tunnel probability for 0.5 nm and 1.00 nm are
and
respectively.