The control setup in this experiment would be one tank that does not contain any of the additives. Since the tanks with the gasoline additives would need to be compared with a tank that is not affected by the results of these additives.
Answer:
Shawn's speed relative to Susan's speed = 10 mph
Resultant velocity = 82.32 mph
Explanation:
The given data :-
i) Susan driving in north and speed of Susan is ( v₁ ) = 53 mph.
ii) Shawn driving in east and speed of Shawn is ( v₂ ) = 63 mph.
iii) The speed of both Susan and Shawn is relative to earth.
iv) The angle between Susan in north and Shawn in east is 90°.
We have to find Shawn's speed relative to Susan's speed.
v₂₁ = v₂ - v₁ = 63 - 53 = 10 mph
Resultant velocity,
![v = \sqrt{v_{2} ^{2}+ v_{1} ^{2} } =\sqrt{63^{2} +53^{2} }](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7Bv_%7B2%7D%20%5E%7B2%7D%2B%20v_%7B1%7D%20%5E%7B2%7D%20%20%7D%20%20%3D%5Csqrt%7B63%5E%7B2%7D%20%2B53%5E%7B2%7D%20%7D)
v = 82.32 mph
Explanation:
We'll need two equations.
v² = v₀² + 2a(x - x₀)
where v is the final velocity, v₀ is the initial velocity, a is the acceleration, x is the final position, and x₀ is the initial position.
x = x₀ + ½ (v + v₀)t
where t is time.
Given:
v = 47.5 m/s
v₀ = 34.3 m/s
x - x₀ = 40100 m
Find: a and t
(47.5)² = (34.3)² + 2a(40100)
a = 0.0135 m/s²
40100 = ½ (47.5 + 34.3)t
t = 980 s
Answer:
took longer to complete one oscillation, that means its PERIOD increased, and the distance between the peaks of the graph would be longer.
line would be less. the period of oscillation would have any effect on the graph
The work W done by the electric field in moving the proton is equal to the difference in electric potential energy of the proton between its initial location and its final location, therefore:
![W= qV_i - qV_f](https://tex.z-dn.net/?f=W%3D%20qV_i%20-%20qV_f)
where q is the charge of the proton,
![q=1 e = 1.6\cdot 10^{-19}C](https://tex.z-dn.net/?f=q%3D1%20e%20%3D%201.6%5Ccdot%2010%5E%7B-19%7DC)
, with
![e](https://tex.z-dn.net/?f=e)
being the elementary charge, and
![V_i = +125 V](https://tex.z-dn.net/?f=V_i%20%3D%20%2B125%20V)
and
![V_f = -55 V](https://tex.z-dn.net/?f=V_f%20%3D%20-55%20V)
are the initial and final voltage.
Substituting, we get (in electronvolts):
![W=e(125 V-(-55 V))=180 eV](https://tex.z-dn.net/?f=W%3De%28125%20V-%28-55%20V%29%29%3D180%20eV)
and in Joule: