1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anestetic [448]
2 years ago
5

A red rubber ball rolls down a hill from rest with an acceleration of 7.8 m/s 2 . How fast is it moving after it has traveled 5

m?
Physics
1 answer:
masya89 [10]2 years ago
7 0

Answer:

39 m/s

Explanation:

You might be interested in
What is the likely identity of a metal if a sample has a mass of 63.5 g when measured in air and an apparent mass of 60.2 g when
Gre4nikov [31]

Answer:

Gold

Explanation:

Given:

Mass of sample = 63.5 g

Mass of water = 60.2 g

Find:

Object

Computation:

Mass of water displaced = 63.5 g - 60.2 g

Mass of water displaced = 3.3 g

So, volume in water = 3.3 cm³

Density = Mass / Volume

Density = 63.5 g / 3.3

Density = 19.24

So,

Object ,must be gold.

7 0
2 years ago
Which of these accurately describes the products of a reaction?
stiv31 [10]
The one that accurately describes the products of a reaction is : B. new substances that are present at the end of a reaction
For example the process of photosynthesis transform CO2 and other nutrients into O2 and H2O

hope this helps
3 0
2 years ago
Read 2 more answers
Which of the following is true about Viscosity of liquids:
White raven [17]
Viscosity of liquids is essentially the 'thickness' of the liquid. For instance, honey and water have different viscosities. Honey has a higher one and therefore, liquids with high viscosity do not flow as well as liquids with low viscosity (water).
4 0
2 years ago
Read 2 more answers
Prior to determining the experimental design, a scientist typically? A. makes observations. B. forms a hypothesis. C. performs a
Umnica [9.8K]

Prior to determining the experimental design, a scientist typically forms a hypothesis. The answer is letter B. this is to prepare the scientist, the possible outcome of their research before the experimental design whether they are wrong or not.

7 0
2 years ago
Suppose that sunlight is incident upon both a pair of reading glasses and a pair of sunglasses. Which pair would you expect to b
Ainat [17]

Answer: the pair of sunglasses

Explanation:

A good pair of sunglasses are composed of abosorbent lenses that filter the sunlight that affects the eyes retina, especially ultraviolet (UV). So, these sunglasses are used to reduce the amount of light or radiant energy transmitted.

On the other hand, normal reading glasses (in which the lens glass has not been treated to filter ultraviolet sunlight) will let UV rays pass through.

Therefore, if both glasses are exposed to sunlight, the sunglasses are expected to be warmer by absorbing that radiant energy and preventing it from reaching the eyes.

4 0
2 years ago
Other questions:
  • Why are metals good conductors of both heat and electricity?
    7·1 answer
  • Which parts of the spectrum show the presence of elements in the stars atmosphere
    5·2 answers
  • A common characteristic of sound waves is that they
    6·1 answer
  • Which situation is work not being done? A) A bookcase is slid across carpeting. B) A stack of books is carried at waist level ac
    7·1 answer
  • How does the law of conservation of mass apply to chemical changes?
    8·2 answers
  • What do you make when you dissolve sugar in water?
    10·1 answer
  • Now consider a different time interval: the interval between the initial kick and the moment when the ball reaches its highest p
    13·1 answer
  • Imagine que su primo Morton baja en patineta por una rampa curva en un parque. Tratando a Morton y su patineta como una partícul
    13·1 answer
  • What I didn't even cross 1000 , how it can be possible...​
    15·1 answer
  • Two astronauts of mass 100 kg are 2 m apart in outer space. What is the
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!