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Romashka-Z-Leto [24]
3 years ago
8

Which of the following best defines

Physics
1 answer:
marta [7]3 years ago
6 0

Answer:

I'd say D

Explanation:

because not all weather happens within the atmosphere, and most weather depends on region (lile if your near the equator or not)

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In a novel from 1866 the author describes a spaceship that is blasted out of a cannon with a speed of about 11.000 m/s. The spac
Elan Coil [88]

Answer:

a=0.284\ m/s^2

Explanation:

Given that,

Initially, the spaceship was at rest, u = 0

Final velocity of the spaceship, v = 11 m/s

Distance accelerated by the spaceship, d = 213 m

We need to find the acceleration experienced by the occupants of the spaceship during the launch. It is a concept based on the equation of kinematics. Using the third equation of motion to find acceleration.

v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(11)^2-(0)^2}{2\times 213}\\\\a=0.284\ m/s^2

So, the acceleration experienced by the occupants of the spaceship is 0.284\ m/s^2.

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3 years ago
Find the velocity of a wave that has a wavelength of 2 meters and a frequency of 2.1Hz
vodomira [7]
It is 4.2 hope i helped

7 0
3 years ago
How are scientific theories and laws similar?
anzhelika [568]
This the answer <span>Often, a law can be expressed in the form of a single mathematical equation. Laws and theories are similar in that they are both scientific statements that result from a tested hypothesis and are supported by scientific evidence. ... A theory, in contrast, is a less concise statement of observed phenomena. i hope this help </span>
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3 years ago
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A student mixed two clear liquids together in a beaker and a solid precipitate formed, this data is shown in the table below . w
klasskru [66]
The mass is 10 +17 +32
8 0
3 years ago
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A thin, uniform, metal bar, 3.00 m long and weighing 90.0 N , is hanging vertically from the ceiling by a frictionless pivot. Su
liraira [26]

Answer:

\omega_f=-2.6rad/s

Since the bar cannot translate, linear momentum is not conserved

Explanation:

By conservation of the angular momentum:

Lo = Lf

I_B*\omega_o+I_b*(V_o/d)=I_B*\omega_f+I_b*(V_f/d)

where

I_B =1/3*M_B*L^2

I_b=m_b*d^2

M_B=90/g=9kg; m_b=3kg; d=1.6m; L=3m; V_o=-10m/s; V_f=5m/s; \omega_o=0 rad/s

Solving for \omega_f:

\omega_f=m_b*d/I_B*(V_o-V_f)

Replacing the values we get:

\omega_f=-2.6rad/s

Since the bar can only rotate (it canno translate), only angular momentum is conserved.

6 0
3 years ago
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