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Natali [406]
3 years ago
15

What does STP and NTP stands for in temperature measurement?

Engineering
1 answer:
Lisa [10]3 years ago
8 0

STP stands for standard temperature pressure and NTP stands for normal temperature pressure

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In your opinion...
ch4aika [34]

Answer:no

TTHANLS FOR FREE POINTS

Explanation:

8 0
2 years ago
Why do engineers play a variety of roles in the engineering process?
katrin2010 [14]

Answer:

b

Explanation:

7 0
2 years ago
After replacing a vacuum booster, the brakes lock up on a road test. Technician A says there is air trapped inside the brake lin
vitfil [10]

Answer:

Technician B

Explanation:

The brakes can lockup due to the following reasons

1) Overheating break systems

2) Use of wrong brake fluid

3) Broken or damaged drum brake backing plates, rotors, or calipers

4) A defective ABS part, or a defective parking mechanism or proportioning valve

5) Brake wheel cylinders, worn off

6) Misaligned power brake booster component

5 0
3 years ago
What are the three most common types of relearn procedures?
WITCHER [35]

Answer:

The three types of relearn procedures are auto relearn, stationary and OBD.

Explanation:

In TPMS system, after the direct service like adjustment of air pressure, tire rotation or replacement of sensors etc, is performed then maximum vehicle  often needs TPMS system relearn that needs to be performed.

For performing these relearn procedure, there are mainly three types:

  1. auto relearn
  2. stationary relearn
  3. OBD

After applying the relearn process, the TPMS system will again be in proper function.

8 0
3 years ago
A plate and frame heat exchanger has 15 plates made of stainless steel that are 1 m tall. The plates are 1 mm thick and 0.6 m wi
hodyreva [135]

Answer:

14.506°C

Explanation:

Given data :

flow rate of water been cooled = 0.011 m^3/s

inlet temp = 30°C + 273 = 303 k

cooling medium temperature = 6°C  + 273 = 279 k

flow rate of cooling medium = 0.02 m^3/s

Determine the outlet temperature

we can determine the outlet temperature by applying the relation below

Heat gained by cooling medium = Heat lost by water

= ( Mcp ( To - 6 )  =  Mcp ( 30 - To )

since the properties of water and the cooling medium ( water ) is the same

= 0.02 ( To - 6 ) = 0.011 ( 30 - To )

= 1.82 ( To - 6 ) = 30 - To

hence To ( outlet temperature ) = 14.506°C

6 0
3 years ago
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