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sdas [7]
3 years ago
8

A 2.5m long steel piano wire has a diameter of 0.5cm how great is the tention in the wire if it stretches by 0.45cm when tighten

ed taking the young's modulus to be 2.0×10^11 N/m^2
Physics
1 answer:
UkoKoshka [18]3 years ago
7 0

Answer:                 Their u go i found it their was about 3 pages i did not no what pages u had to do.

Explanation:

Download pdf
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A volleyball player hit he ball with a mass of .25 kg. the average acceleration of the ball is 15.5 m/s^2. how much force did th
sukhopar [10]
F=MA - equation
F=(0.25 kg)(15.5 m/s^2) - multiply the mass and the acceleration
F= 3.875 N - N means Newton (SI unit for force)
Hope this helps 
6 0
4 years ago
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If 1.3 grams of air has a volume of 1000cm ^3, what is the density of air?
sleet_krkn [62]
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Density is equal to mass/volume, so in your case:
density=1.3/1000=0.0013 g/cm^3
5 0
3 years ago
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The distance between the centers of the wheels of a motorcycle is 156 cm. The center of mass of the motorcycle, including the ri
Drupady [299]

Answer:

a = 9.86 m/s²

Explanation:

given,

distance between the centers of wheel = 156 cm

center of mass of motorcycle including rider = 77.5 cm

horizontal acceleration of motor cycle = ?

now,

The moment created by the wheels must equal the moment created by gravity.

take moment about wheel as it touches the ground, here we will take horizontal distance between them.

then, take the moment around the center of mass. Since the force on the ground from the wheels is horizontal, we need the vertical distance.

now equating both the moment

m g d = F h

d is the horizontal distance

h is the vertical distance

m g d = m a h

term of mass get eliminated

g d = a h

so,

a = \dfrac{g\ d}{h}

a = \dfrac{9.8\times 0.78}{0.775}

a = 9.86 m/s²

4 0
3 years ago
The terminal velocity of a person falling in air depends upon the weight and the area of the person facing the fluid.
kolbaska11 [484]

Answer:

The terminal velocity of the diver is 115 m/s = 414 km/hr

Explanation:

At terminal velocity,

Fnet = mg - Fd = 0

Drag force, Fd = cρAv²/2

mg = cρAv²/2

Terminal Velocity of a body falling through a fluid as in a diver falling through air is given by

v = √(2mg/ρcA)

where m = mass of body falling through fluid = 80 kg

g = acceleration due to gravity = 9.8 m/s²

ρ = density fluid, density of air, as obtained from literature = 1.21 kg/m³

c = coefficient of drag friction of diver falling through air, as obtained from literature = 0.7

A = the area of the diver facing the fluid = 0.14 m²

v = √(2mg/ρcA) = √((2 × 80 × 9.8)/(1.21 × 0.7 × 0.14)) = 115 m/s = 115 × (3600/1000) km/hr = 414 km/hr

5 0
3 years ago
3. How does Earth’s rotation affect our view of stars
Elis [28]
Since we ride along with the Earth while it's doing whatever it does,
the Earth's rotation causes our eyes to constantly point in a different
direction.

If we try to keep watching one star, we have to keep changing the
direction of our eyes to keep looking at the same star. 

We can't feel the Earth rotating, so our brains say that the star  ... and
the sun and the moon too ... is actually moving across the sky.
5 0
3 years ago
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