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Lilit [14]
3 years ago
7

If there is an increase in demand for a product, and that is the only thing that changes, what will that do to the price of the

product?
Physics
2 answers:
Eva8 [605]3 years ago
5 0
I believe that the price will rise.
Hope this helps!
lozanna [386]3 years ago
4 0

Answer:

Price will also increase.

Explanation:

If there is an increase in demand for a product, keeping other factors constant, price of product will also rise. According price demand curve demand of a product and price of product in direct proportional relationship with each other. So as demand of any product increases, its price will also increase simultaneously.

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Answer: B, Companies passed on production and transportation costs to consumers

Explanation:

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Select all of the answers that apply. which of the following cause volcanic eruptions?
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I think it's A. Pressure and heat built up in the magma chamber.
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Which explanation is least likely to be evidence for geological processes changing Earth's surface?
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Pollution isn’t a geological process.
3 0
2 years ago
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Complete the passage.
nataly862011 [7]

Answer:

Answer: Sound waves and some earthquake waves are longitudinal waves. Ocean, light and other earthquake waves are transverse waves.

Explanation:

There are 2 types of waves:

1. Longitudinal waves: These waves are defined as the waves in which the particles of the medium move in the direction of the wave. This requires a medium to travel. For Example: Sound Waves.

2. Transverse wave: These waves are defined as the waves in which the particles of the medium travel perpendicularly to the direction of the wave. This does not require a medium to travel. These can travel in vacuum also. For Example: Light waves.

Hence, Sound waves and some earthquake waves are longitudinal waves. Ocean, light and other earthquake waves are transverse waves

8 0
2 years ago
Water is flowing in a pipe with a varying cross-sectional area, and at all points the water completely fills the pipe. At point
RideAnS [48]

Answer:

a) 2.33 m/s

b) 5.21 m/s

c) 882 m³

Explanation:

Using the concept of continuity equation

for flow through pipes

A_{1}\times V_{1} = A_{2}\times V_{2}

Where,

A = Area of cross-section

V = Velocity of fluid at the particular cross-section

given:

A_{1} = 0.070 m^{2}

V_{1} = 3.50 m/s

a) A_{2} = 0.105 m^{2}

substituting the values in the continuity equation, we get

0.070\times 3.50 = 0.105\times V_{2}

or

V_{2} = \frac{0.070\times 3.5}{0.150}m/s

or

V_{2} = 2.33m/s

b) A_{2} = 0.047 m^{2}

substituting the values in the continuity equation, we get

0.070\times 3.50 = 0.047\times V_{2}

or

V_{2} = \frac{0.070\times 3.5}{0.047}m/s

or

V_{2} = 5.21m/s

c) we have,

DischargeQ = Area (A)\times Velocity(V)

thus from the given value, we get

Q = 0.070m^{2}\times 3.5m/s\

Q = 0.245 m^{3}/s

Also,

DischargeQ = \frac{volume}{time}

given time = 1 hour = 1 ×3600 seconds

substituting the value of discharge and time in the above equation, we get

0.245m^{3}/s = \frac{volume}{3600s}

or

0.245m^{3}/s\times 3600 = Volume

volume of flow = 882 m^{3}

8 0
3 years ago
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