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Zielflug [23.3K]
3 years ago
10

The fulcrum is the

Physics
1 answer:
olga_2 [115]3 years ago
6 0

Answer:

point of support on which a lever rotates.

Explanation:

The fulcrum is the point of support on which a lever rotates. Fulcrum is a pivotal part of simple machines.

The fulcrum provides the platform for a lever to torque.

  • The force that opposes motion by the applied force is termed the frictional force.
  • Friction is a force that opposes motion.
  • The stored energy of an object is its potential energy.
  • The potential energy is the energy due to the position of a body.
  • The distance an object moves when doing work is termed its displacement.
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On the earth, when an astronaut throws a 0.250-kg stone vertically upward, it returns to his hand a time T later. On planet X he
Liula [17]

Answer:

correct is d) a ’= g / 2

Explanation:

For this exercise let's use the kinematics equations

On earth

      v = v₀ - a t

     a = (v₀- v) / T

On planet X

    v = v₀ - a' t’

    a ’= (v₀-v) / 2T

Let's substitute the land values ​​in plot X

     a’= a / 2

Now let's use Newton's second law

       W = ma

      m g = m a

      a = g

We substitute

      a ’= g / 2

So we see that on planet X the acceleration is half the acceleration of Earth's gravity

4 0
2 years ago
Answer question quick
Anettt [7]

Answer:

Yes , insulation has no role

5 0
3 years ago
Find the momentum of a 25kg object traveling at a speed of 4m/s
solong [7]

Answer:

100Kg.m/s

Explanation:

From the question, we obtained the following information:

M= Mass = 25kg

V = Velocity = 4m/s

Momentum =?

Momentum = MV = 25x4= 100Kg.m/s

8 0
3 years ago
Help, please. I am not sure what to do.
miss Akunina [59]

Answer:

option D) -3m

Explanation:

if 6m is diplaced by -3m then it would be -3+6=3m

feel free to ask if you are confused

3 0
2 years ago
A 1300 kg car starts at rest and rolls down a hill from a height of 10.0 m. It then moves across a
Makovka662 [10]

Answer:

0.51 m

Explanation:

Using the principle of conservation of energy, change in potential energy equals to the change in kinetic energy of the spring.

Kinetic energy, KE=½kx²

Where k is spring constant and x is the compression of spring

Potential energy, PE=mgh

Where g is acceleration due to gravity, h is height and m is mass

Equating KE=PE

mgh=½kx²

Making x the subject of formula

x=\sqrt {\frac {2mgh}{k}}

Substituting 9.81 m/s² for g, 1300 kg for m, 10m for h and 1000000 for k then

x=\sqrt \frac {2*1300*9.81*10}{1000000}=0.50503465227646m\\x\approx 0.51 m

5 0
3 years ago
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